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cestrela7 [59]
3 years ago
13

If someone is riding in the back of a pickup truck and throws a softball straight backward, is it possible for the ball to fall

straight down as viewed by a person standing at the side of the road? Under what condition would this occur? How would the motion of the ball appear to the person who threw it?
Physics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

The person on the truck would have the same speed as that of the truck. Also, before the ball is thrown, the ball would have the speed as that of the truck.

It is possible for a person standing at the side of the road to view the falling straight down.  This would be possible if the ball is thrown backwards with the same magnitude of velocity as that of truck.

To the person on the truck, the ball would appear to have forward motion with the speed of the truck.

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maxonik [38]
Hello! mark me brainliest please

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time.
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3 years ago
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A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc
ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

T=2\pi \sqrt{\frac{L}{g} }

Where T is period

           L is length of rod

       g is acceleration due to gravity =     9.8m/s^{2}

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this L_{O}

L_{O} = 3/4 * 5.95m

        = 4.4625m

thus   T=2\pi \sqrt{\frac{L_{O} }{g} }

          T=2\pi \sqrt{\frac{4.4625 }{9.8} }

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8 0
4 years ago
Which phrase desenbes an irregular galaxy ?
Andrews [41]

Answer:

contains many young stars

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The "spiral galaxy" is the type of galaxy that has arms that extend from the center. These arms look "spiral," which influenced its name. This makes the last choice incorrect.

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A 100 g cart is moving at 0.5 m/s that collides elastically from a stationary 180 g cart. Final velocity is calculated to be 0.25m/s.

Collision in which there is no net loss in kinetic energy in the system as a result of the collision is known as elastic collision . Momentum and kinetic energy both are conserved quantities in elastic collisions.

Collision in which part of the kinetic energy is changed to some other form of energy is inelastic collision.

For an elastic collision, we use the formula,

m₁V₁i+ m₂V₂i = m₁V1f + m₂V₂f

For a perfectly elastic collision, the final velocity of the 100g cart will each be 1/2 the velocity of the initial velocity of the moving cart.

Final velocity = 0.5/2

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brainly.com/question/7694106

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