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nikdorinn [45]
3 years ago
13

The planet Venus has a mass of 4.87 × 1024 kg and a radius of 6.05 × 106 km. What is the magnitude of the gravitational force th

at an 81-kg person would experience while standing on the surface of Venus?
Physics
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

7.2 x 10⁻⁶N

Explanation:

Given parameters:

Mass of Venus  = 4.87 x 10²⁴kg

Radius  = 6.05 x 10⁶km = 6.05 x 10⁹m

Mass of person  = 81kg

Unknown:

Gravitational force  = ?

Solution:

To solve this problem, we use the Newtons law of universal gravitation:

  Fg  = \frac{G x mass of venus x mass of person}{radius^{2} }  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹

 Fg  = \frac{6.67 x 10^{-11}  x 4.87 x 10^{22} x 81 }{(6.05 x 10^9)^{2} } }

 Fg  =  7.2 x 10⁻⁶N

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An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and
Kobotan [32]

Answer:

Explanation:

Given that

The electric fields of strengths E = 187,500 V/m and

and The magnetic  fields of strengths B = 0.1250 T

The diameter d is 25.05 cm which is converted to 0.2505m

The radius is (d/2)

= 0.2505m / 2 = 0.12525m

The given formula to find the magnetic force is F_{ma}=BqV---(i)

The given formula to find the electric force is F_{el}=qE---(ii)

The velocity of electric field and magnetic field is said to be perpendicular

Electric field is equal to magnectic field

Equate equation (i) and equation (ii)

Bqv=qE\\\\v=\frac{E}{B}

v=\frac{187500}{0.125} \\\\v=15\times10^5m/s

It is said that the particles moves in semi circle, so we are going to consider using centripetal force

F_{ce}=\frac{mv^2}{r}---(iii)

magnectic field is equal to centripetal force

Lets equate equation (i) and (iii)

Bqr=\frac{mv^2}{r} \\\\\frac{q}{m}=\frac{v}{Br}  \\\\\frac{q}{m} =\frac{15\times 10^5}{0.125\times0.12525} \\\\=\frac{15\times10^5}{0.015656} \\\\=95808383.23\\\\=958.1\times10^5C/kg

Therefore,  the particle's charge-to-mass ratio is 958.1\times10^5C/kg

b)

To identify the particle

Then 1/ 958.1 × 10⁵ C/kg

The charge to mass ratio is very close to that of a proton, which is about 1*10^8 C/kg

Therefore the particle is proton.

8 0
4 years ago
a metal sphere with a mass of 90 kg rolls along at 16m/s and strikes a stationary sphere having a mass of 140kg. the first spher
baherus [9]
13.2 meters per second
7 0
3 years ago
Two magnets are placed near each other on a space station orbiting Earth.
dimulka [17.4K]

Answer: A. They will be repelled because they are in each other's magnetic

field.

Explanation: Apex and gravity and electrical don't have effect on magnets magnetic field.

5 0
3 years ago
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A 6 kg cart starting from rest rolls down a hill and at the bottom has a speed of 10 m/s. What is the height of the hill?
Arisa [49]

Answer:

h = 5.09 m

Explanation:

Applying the Law of conservation of energy to this situation, we can write:

Kinetic\ Energy\ Gained\ by\ the\ Cart = Potential\ Energy\ Lost\ by\ the\ Cart\\\frac{1}{2}mv^2 = mgh\\\\h = \frac{v^2}{2g}

where,

h = height of the hill = ?

v = speed of cart at the end = 10 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

h = \frac{(10\ m/s)^2}{(2)(9.81\ m/s^2)}\\\\

<u>h = 5.09 m</u>

4 0
3 years ago
The Skeleton does a surprising number of things. What are the three main Ones? lol, it's due today at 12:59 pm I need help.
ICE Princess25 [194]

Answer:

Support

Posture

Protection

Explanation:

Support – the skeleton keeps the body upright and provides a framework for muscle and tissue attachment.

Posture – the skeleton gives the correct shape to our body.

Protection – the bones of the skeleton protect the internal organs and reduce the risk of injury on impact.

5 0
3 years ago
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