Question

What is the amplitude of an AC voltage waveform, in units of Volts, if the RMS value is 369 V?

Answer 1

Answer:

521.8 V

Explanation:

The RMS value of the voltage of an AC signal is given by

$V_{rms}=\frac{V_0}{\sqrt{2}}$

where

$V_0$ is the peak voltage, which corresponds to the amplitude of the AC waveform

In this problem, we know the RMS voltage

$V_{rms}=369 V$

Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):

$V_0 = \sqrt{2}V_{rms}=\sqrt{2}(369 V)=521.8 V$