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ArbitrLikvidat [17]
3 years ago
7

What is the amplitude of an AC voltage waveform, in units of Volts, if the RMS value is 369 V?

Physics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

521.8 V

Explanation:

The RMS value of the voltage of an AC signal is given by

V_{rms}=\frac{V_0}{\sqrt{2}}

where

V_0 is the peak voltage, which corresponds to the amplitude of the AC waveform

In this problem, we know the RMS voltage

V_{rms}=369 V

Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):

V_0 = \sqrt{2}V_{rms}=\sqrt{2}(369 V)=521.8 V

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You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo
S_A_V [24]

Answer:

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

Z=\sqrt{R^2+\omega^2L^2}       (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

I=\frac{V}{Z}                     (2)

V: voltage amplitude = 30.0V

I=\frac{30.0V}{185.87\Omega}=0.16A

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV            (3)

D. The voltage across the inductor is:

V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V

E. The phase difference is given by:

\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°

5 0
3 years ago
How do solar panels create electricity
xenn [34]

Answer:

They create electricity from the sun's  rays

Explanation:

By the use of "solar cells" or "solar panel", you can trap solar energy in silicon/germanium rods, then you can convert in into electricity too. Solar powered panels convert the sun's rays into electricity by exciting electrons in silicon cells using the photons of light from the sun. This electricity can then be used to supply renewable energy to your home or business.

5 0
3 years ago
A 10 kg box slides down a lane inclined at an angle θ = 30 . The plane has a friction of coefficient 0.1. The box starts from th
g100num [7]

Answer:

The distance the box traveled down the plane is 19.28 m

Explanation:

The angle of repose, α, is given by the relation;

tan⁻¹(μ) = α

tan⁻¹(0.1) = 5.7°

Therefore, we have;

M·g·sin(θ) - μ·N = M·a

Where:

M = Mass of the box = 10 kg

g = Acceleration due to gravity = 9.81 m/s²

θ = Angle of inclination of the plane = 30°°

μ = Coefficient of friction = 0.1

a = Acceleration of the box along the incline plane

N = Normal force due to the weight of the box = M·g·cos(θ)

10 × 9.81 × sin30 - 0.1 × 9.81 × cos(30)  = 10 × a

48.2 = 10 ×a

a = 48.2/10 = 4.82 m/s²

The distance, s, traveled by the box is given by the relation;

s = u·t + 1/2×a·t²

Where:

u = Initial velocity = 0 m/s

t = Time of motion = 2.0 s

∴ s = 0×2 + 1/2 × 4.8 × 2² = 19.28 m

The box traveled 19.28 m down the plane.

6 0
3 years ago
A motorcycle starts at rest and accelerates at a rate of 3 meters per second squared (m/s2) over a time period of 5 seconds (s).
Alex787 [66]
Final velocity = 3 x 5 = 15 m/s
5 0
3 years ago
An electrical current flowing through a filament bulb causes it to get hot. Explain why this
sergij07 [2.7K]

Answer:

The reason the filament heats up is because it has a high resistance, which means that as electrons move through the filament, they lose a lot of energy.

First, what is current? Current is comprised of electrons moving through an electric field from a high electric potential to a lower potential. For the current to decrease then, something would need to happen to the electrons that go into the light bulb.  If 1 electron goes into the light bulb, then at the end of everything I need to still have 1 electron someplace. So how do electrons passing through the bulb make light?

Incandescent light bulbs have a small filament which when heated begins to glow and emit light.  The reason the filament heats up is because it has a high resistance, which means that as electrons move through the filament, they lose a lot of energy.  You can think of it as walking on a sidewalk compared to walking in waist deep water.  A wire is like a sidewalk. It has some resistance, but it is so tiny that it can generally be ignored which is why wires are useful in electronic circuits. The high resistance of the light bulb is like trying to walk through waist deep water.  Here energy is being taken from the electrons because of the interactions with the atoms in filament which causes those atoms to heat up, which in turn makes them emit light.

The light bulb is not doing anything to the electrons, so we expect then that any electrons going into the bulb should come out the other side. Since current is just flowing electrons, current stays the same.

Since current is the same on both sides, we know that the electrons are all moving together. Think of it like being in a big loop of people. Since everyone is in a big line you could imagine that you could only move as fast as the slowest person in the line. If everyone is on a big loop of sidewalk then everyone could run around in a circle. This is like having a large current in a loop of wire, or what we call a short. To put the equivalent of a lightbulb into our human circuit, imagine that one section of the sidewalk dips into a pool of water. Now everyone is stuck going as fast as the people trudging through the water. This is why current everywhere in a circuit is smaller when a resistor is introduced. As people trudge through the water they have to work hard to get through the water and they use energy.  In a circuit, this energy comes from the voltage source, like a battery.  The battery loses energy because it has to "pull" the electrons through the high resistance, and this is why the voltage drops across the light bulb

7 0
3 years ago
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