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tankabanditka [31]

2 years ago

14

The distance around our schools playing field is 300 meters. if our coach wants us to run 3 kilometers how many times will we ne

ed to run around the filed

1 answer:

galina1969 [7]2 years ago

8 0

3 kilometers is equal to 3000 meters
Distance of a ground is 300 meters sou need to run 10 rounds around thefield

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bogdanovich [222]

Is the question your asking the one at the bottom

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2 years ago

Explain how System 1 becomes equivalent to System 2.

Nostrana [21]

Answer:

$\left\{\begin{array}{ccc}(A+L)x+(B+M)y=C+N\\Ax+By=C\end{array}\right$

<h3>A.The first equation in System 2 is the sum of the equations in System 1. The second equation in System 2 is the first equation in System 1.</h3>

Step-by-step explanation:

$\underline{+\left\{\begin{array}{ccc}Ax+By=C\\Lx+My=N\end{array}\right}\qquad\text{add both sides of the equations}\\(Ax+Lx)+(By+My)=C+N\qquad\text{distributive}\\(A+L)x+(B+M)y=C+N$

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2 years ago

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Mark is going to an awards dinner and wants to dress appropriately. He is running behind schedule and asks his little brother to

Cerrena [4.2K]

Answer:

The answer is " $\bold{\frac{2}{3}}$ ".

Step-by-step explanation:

Pick a shirt first: 3 choices

Pick slacks next: 2 choices

Then choose a tie: 1 choice

Total: $3 \times 2 \times 1 = 6$ outfits.

These will be similarly divided between the two slacks, so 3 black slack outfits of $6 = \frac{1}{2}$ . Similarly, the 6 styles are also divided between the option of 3 shirts. 2 blue shirt outfits $6 = \frac{1}{3}$

To recognize that over outfits are a mix of a blue shirt and black slack, it would be twice many more to add $\frac{1}{2} \ and \ \frac{1}{3}$ . Add $\frac{1}{2} \ and \ \frac{1}{3}$ , and remove the chance for both the black slack shirt and outfit and are one of the six outfits:

$\to \frac{1}{2} + \frac{1}{3} -\frac{1}{6} =\frac{3+2-1}{6} =\frac{4}{6} = \frac{2}{3}$

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2 years ago

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natta225 [31]

3y = x - 1...I am going to re-arrange this.....-x + 3y = -1

-x + 3y = -1
x - 2y = 2
---------------add...u will notice that the x's cancel
y = 1

3y = x - 1
3(1) = x - 1
3 = x - 1
3 + 1 = x
4 = x

solution is (4,1)

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Mekhanik [1.2K]

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