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uranmaximum [27]
3 years ago
13

The double number line below shows the approximate number of kilograms in a certain number of pounds

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
3 pounds = 1.5 kilograms
so 9 pounds = 1.5 * 3 = 4.5 kilograms
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{x/x is an even whole number less than 7)
pentagon [3]

Answer:

yea

because if 1/2=2/4=4/8=8/16 see all are equal to the number of the amount of a whole number

7 0
3 years ago
7 copies of the sum of 8 fifths and 4
Serggg [28]
So what you would do is 8/5 + 4 x 7 = 26.9
then you round it to 30
7 0
3 years ago
Find the global maximum and global minimum values (if they exist) of x 2 + y 2 in the region x + y = 1. If there is no global ma
Grace [21]

Given that x+y=1, we have y=1-x, so that

f(x,y)=x^2+y^2\iff g(x)=x^2+(1-x)^2

Take the derivative and find the critical points of g:

g'(x)=2x-2(1-x)=4x-2=0\implies x=\dfrac12

Take the second derivative and evaluate it at the critical point:

g''(x)=4>0

Since g'' is positive for all x, the critical point is a minimum.

At the critical point, we get the minimum value g\left(\frac12\right)=f\left(\frac12,\frac12\right)=\frac12.

5 0
3 years ago
What is the sum of all the integers between the square root of 10 and the square root of 47
insens350 [35]
First estimate the square root of 10, about 3.16
and then the square root of 47, about 6.85
now what are the integers in between 3.16 and 6.85:
4,5,6
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=15
Hope this helps.
5 0
3 years ago
Read 2 more answers
A bicycle manufacturing plant is producing the first few frames for their new electric bicycle design. The first batch of 60 fra
Dmitry_Shevchenko [17]

Answer:

a) 131/450

b) 1233/1276  

Step-by-step explanation:

P(bad) = P(1st batch)*P(bad 1st batch ) + P(2nd batch )*P(bad 2nd batch) + P(3rd batch )*P(bad 3rd batch)

p(bad) =(60/360)*(1/3) + (120/360)*(1/4 ) + (180/360)*(1/5)

= 43/180  

And that of  P(good )

= 1 - 43/180

= 137/180

a)

P(defective) = P(bad)*P(defective /bad) + P(good)*P(defective /good)

= (43/180)*(9/10) + (137/180)*(1/10)

= 131/450

b)

P(Bc I Dc ) = P(good)*P(not defective |good) / P(not defective)

= (137/180)*(1 - 1/10) / (1 - 131/450)

= 1233/1276  

5 0
3 years ago
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