All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer would be -4 5/12
Hope that helps.
Answer:
17 + 2i
Step-by-step explanation:
Given
(2 - 3i) + 5i(1 - 3i) ← distribute both parenthesis
= 2 - 3i + 5i - 15i² [ i² = - 1 ]
= 2 + 2i + 15
= 17 + 2i ← in standard form