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aliina [53]
3 years ago
7

A student pulls a 60 Newton sled with a force having a magnitude of 20 Newton’s. What is the magnitude of the force that the sle

d exerts on the student
Physics
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

20 Newtons

Explanation:

According to Newton's Third Law, the sled exerts a force equal in magnitude and opposite in direction to the force that pulls it, which is 20 Newtons. Given the information about the magnitude of the pulling force, the weight of the sled is irrelevant.

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According to the principle of overload you should __________.
valentinak56 [21]
According to the principle of overload, you should A. GRADUALLY INCREASE THE DIFFICULTY OF A WORKOUT.

It is the state wherein a greater than normal stress or load on the body is required for training adaptation to take place.


6 0
4 years ago
Read 2 more answers
Suppose the B string on a guitar is 24" long and vibrates with a frequency of about 247 Hz. You place your finger on the 5th fre
Rudiy27

Answer:

b. E (about 329 Hz)

Explanation:

Given data:

Initial length of the string l1= 24 in

initial frequency f1= 247 Hz

changed length l2= 18 in

Then we have to find the changed frequency f2= ?

We already now that

frequency f ∝ 1/length of the string l

therefore,

\frac{f_1}{f_2} =\frac{l_1}{l_2}

⇒{f_2}=\frac{l_1}{l_2}\times{f_1}

⇒{f_2}=\frac{24}{18}\times{247}

⇒{f_2}=329.33 Hz

7 0
3 years ago
A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
s344n2d4d5 [400]

Answer:

309 m

Explanation:

time apart = 0.8 s

speed of sound in air = 343 m/s

speed of sound in concrete = 3000 m/s

lets assume it time it takes to travel trough concrete = T

the time it takes to travel through air = T + 0.8 since they are 0.8 s apart

the distance traveled by both waves is the same, so we can equate the distance for both waves

distance  = speed x time

  • for concrete, distance = 3000 x T
  • for air, distance = 343 x (T + 0.8)

now equating the two distance together we have

3000 x T  = 343 x (T + 0.8)

3000T = 343T + 274.4

3000T - 343T = 274.4

T = 0.103 s

recall that distance = 3000 x T = 3000 x 0.103 = 309 m

5 0
3 years ago
what frequency of light must an electron in hydrogen absorb to jump from the n=2 state to the n=5 state? (a) 2.86 Hz (b) 4.08 Hz
Ostrovityanka [42]

Answer:

(c) 6.91x10^14 Hz

Explanation:

Find the level energy of n=2 and n=5, using  the formula:

E = -E_0/n^2

where  E_0=13.6eV

E_2 =\frac{-13.6}{2^2}=-3.4eV

E_5 =\frac{-13.6}{5^2}=-0.544eV

To jump from n=2 to n=5 the electron absorbs a photon with energy equal to (-0.544) - (-3.4)=2.856eV, using the next formula to find specific wavelength \lambda to that energy

E = hc/\lambda

Where c is the speed of light (c=3 \times10^8m/s) and h is Planck's constant (h=4.14\times10^{-15}eVs). Solve for \lambda:

E = hc/\lambda\\\lambda E = hc\\\lambda = \frac{hc}{E} \\\lambda = \frac{(4.14\times10^{-15})(3 \times10^8)}{2.856}=4.35\times10^{-7}m

The frequency of this wavelength is calculated with this formula:

f=\frac{c}{\lambda}

f=\frac{3\times10^8}{4.3487\times10^{-7}} =6.89\times10^{14}Hz\approx6.9\times10^{14}Hz

8 0
4 years ago
URGENT ANSWER ASAP PLEASE
irakobra [83]

Answer:

learning and memory are very closely related concept . Learning is the acquisition of silk or knowledge, while memory is the expression of what you've acquired.Another difference is the speed with which the two things happen if you acquire the new skill or knowledge slowly and laboriously, that's learning

5 0
3 years ago
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