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melomori [17]
3 years ago
7

URGENT ANSWER ASAP PLEASE

Physics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

learning and memory are very closely related concept . Learning is the acquisition of silk or knowledge, while memory is the expression of what you've acquired.Another difference is the speed with which the two things happen if you acquire the new skill or knowledge slowly and laboriously, that's learning

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I have another one of these similar to it, if you need another 20 points then look in my profile.
zimovet [89]

Answer:

NEW

Explanation:

As the moon moves to position Z it becomes a New moon due to the light of the sun shining on it

8 0
2 years ago
Read 2 more answers
Name some differences between a motor and an electromagnet
Darya [45]
Differences b/w an motor n an electromagnet r :

1- motor is a device which converts electrical energy into mechanical energy while an electromagnet is just a combination of a soft iron core + solenoid....

2- electromagnets r strong temporary magnets while motors don't behave like a magnet
7 0
2 years ago
Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in fron
TiliK225 [7]

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m

Next, you calculate the wavelength of the sound waves by using the following formula:

\lambda=\frac{v_s}{f}

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

\lambda=\frac{343m/s}{400Hz}=0.8575m

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\Delta d=3.827m-2.10m=1.727m

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2

Then, there will be a constructive interference, and the sound who the observer hears is loud.

5 0
3 years ago
This is an example of using a hammer as a(n)
barxatty [35]

, to hit nails into a piece of wood or a wall, or to break things into pieces.

3 0
3 years ago
Read 2 more answers
A block is attached to a horizontal spring and oscillates back and forth on a frictionless horizontal surface at a frequency of
Nastasia [14]

Answer:

Amplitude = 0.058m

Frequency = 6.25Hz

Explanation:

Given

Amplitude (A) = 8.26 x 10-2 m

Frequency (f) = 4.42Hz

Conversation of energy before split

½mv² = ½KA²

Make A the subject of formula

A = v\sqrt{\frac{m}{k} }

Conversation of energy after split

½(m/2)V'² = ½(m/2)V² = ½KA'²

½(m/2)V² = ½KA'²

Make A the subject of formula

First divide both sides by ½

(m/2)V² = KA'²

Divide both sides by K

\frac{m}{2K}V² = A'²

v\sqrt{\frac{m}{2k} } = A'

Substitute v\sqrt{\frac{m}{k} } for A in the above equation

A' = A/√2

A' = 8.26 x 10^-2/√2

A' = 0.05840702012600882

Amplitude after split = 0.058 (Approximated)

Frequency (f') = f√2

f' = 4.42√2

f' = 6.25082394568908011

Frequency after split = 6.25Hz (approximated)

8 0
3 years ago
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