3 years ago

A line _____ on a typical Speed vs. Time graph means an object is experiencing a constant acceleration.

Physics

2 answers:

Savatey [412]3 years ago

7 0

Answer:

The answer should be C. slanted upward to the right.

Hope this helps. :-)

Mila [183]3 years ago

4 0

C should be your answer

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Transcranial magnetic stimulation (TMS) is a noninvasive technique used to stimulate regions of the human brain. A small coil is

attashe74 [19]

Answer:

0.125 volts

Explanation:

The induced emf can be sufficient to stimulate neuronal activity.

One such device generates a magnetic field within the brain that rises from zero to 1.5 T in 120 ms.

We need to find the induced emf within a circle of tissue of radius 1.6 mm and that is perpendicular to the direction of the field. The formula for the induced emf is given by :

$\epsilon=-\dfrac{d\phi}{dt}$

Where

$\phi$ is magnetic flux

So,

$\epsilon=-\dfrac{d(BA)}{dt}\\\\=2\pi r\times \dfrac{dB}{dt}\\\\=2\pi \times 1.6\times 10^{-3}\times \dfrac{1.5-0}{120\times 10^{-3}}\\\\=0.125\ V$

So, the induced emf is equal to 0.125 volts.

7 0

3 years ago

What is the average (mean) of these numbers: 13,43, 12, 3,66

algol13

Answer:

27.4

Explanation:

(13+43+12+3+66)/5

137/5

27.4

3 0

3 years ago

Read 2 more answers

Please help me with this question...

vredina [299]

The answer is B (The second one). I'm not sure though.

3 0

3 years ago

a block of wood of density 0.8 gram per centimetre cube has a volume of 60 cm3 the mass of block will be...?

Tamiku [17]

Density =mass/Volume

0.8=mass/60
Mass=0.8*60
Mass=48g

4 0

2 years ago

If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed? F_e final/F_e, in

motikmotik

To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

$F_{initial} = \frac{kq_1q_2}{r^2}$

Here,

k = Coulomb's constant

$q_{1,2}$ = Charge at each object

r = Distance between them

As the distance is doubled so,

$F_{final} = \frac{kq_1q_2}{( 2r )^2}$

$F_{final} = \frac{ kq_1q_2}{ 4r^2}$

$F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}$

$F_{final} = \frac{1}{4} F_{initial}$

$\frac{F_{final}}{ F_{initial}} = \frac{1}{4}$

Therefore the factor is 1/4

6 0

3 years ago