Given statement is "What is the intersection of the given lines AE and DE?".
That gives us information that there are two lines named AE and DE which intersect each other. Now we have to find their intersection point.
If you see carefully the name of both lines AE and DE then you will find that; they have common letter "E" in their name.
That means point "E" lies on both lines.
We know that intersection point always lies on both lines.
Which proves that point "E" is the intersection point.
Hence choice "<u>B. Point E" </u>is the final answer.
-4/8 i think that is right not sure tho so you might wanna wait for ohter answer
Answer:- 29
false
Step-by-step explanation:
If you would like to write x^4y - 4x^2y - 5y in a completely factored form, you can do this using the following steps:
x^4y - 4x^2y - 5y = y * (x^4 - 4x^2 - 5) = y * (x^2 + 1) * (x^2 - 5)
The correct result would be <span>y * (x^2 + 1) * (x^2 - 5).</span>
n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
