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Triss [41]
3 years ago
5

if i measure a hypotenuse and i get 11 and then i double check my work by doing the a squared + b squared = c squared method and

i get 12 why would these two be different
Mathematics
1 answer:
RoseWind [281]3 years ago
5 0
Hi there!

Sometimes, like you said, you might don't get the exact answer when you justified your answer. In this case, you need to take the nearest number. So if you got 11 then 12 is the nearest number, just go for it.

Or go back and start over and see if you didn't miss anything.


I hope this helps!
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The value of x is 5\sqrt[3]{25}.

Solution:

Given expression is -7=8-3 \sqrt[5]{x^{3}}.

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8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

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The 3rd term of the geometrical sequence is larger than the 2nd
notsponge [240]

Answer:the first term is 81

Step-by-step explanation:

The formula for determining the nth term of a geometric sequence is expressed as

Tn = ar^(n - 1)

Where

Tn represents the nth term

n represents the number of terms

r represents the common ratio

The 3rd term of the geometrical sequence is larger than the 2nd

term by 36. This means that

T3 - T2 = 36 - - - - - - - - - - 1

The product of these two terms is -243. This means that

T2 × T3 = - 243

T2 = - 243/T3

Substituting T2 = - 243/T3 into equation 1, it becomes

T3 - (- 243/T3) = 36

T3 + 243/T3 = 36

T3^2 + 243 = 36T3

T3^2 - 36T3 + 243 = 0

T3^2 - 27T - 9T3 + 243 = 0

T3(T3 - 27) - 9(T3 - 27) = 0

T3 - 9 = 0 or T3 - 27 = 0

T3 = 9 or T3 = 27

Substituting T3 = 9 or T3 = 27 into

T2 = - 243/T3 = 27, it becomes

T2 = - 243/9 or - 243/27

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Therefore,

The 3rd term is 9

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The expression for the third term would be

9 = a × - 1/3^(3 - 1)

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Answer:

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Step-by-step explanation:

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