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3 years ago

Please help me I need this done not a lot of work but please get it done with good credit for good rating and reward!

Mathematics

1 answer:

goldenfox [79]3 years ago

6 0

Answer:

1. Diameter

2. more than 1 but less than 2

3. ans: 3.14

4. ans: 3.142

5. 33.7 inches

6. a) 100.57 b) 2.36 (2 dp) c) 236.66 d) 113.14 e)20.11

f) 86.11

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Which quadratic rule represents the data in the table?

Vaselesa [24]

Answer:

x^2 - 5

Step-by-step explanation:

x = -1, y = 1 - 5 = -4.

x = 0, y = 0-5 = -5.

x = 1, y = 1 - 5 = -4.

7 0

3 years ago

What is the IQR (Inter Quartile Range) for the data set? 11 6 19 14 21 7 13 15 15 Question 10 options: 8 9 15 17

Gnesinka [82]

IQR is the Q3 - Q1

Put the data in order.....

6, 7, 11, 13, 14, 15, 15, 19, 21
^ ^ ^
9(Q1) 14(Q2) 17(Q3)

17 (Q3) - 9 (Q1) = 8 (IQR)

So the answer to your question is the first option, 8.

Hope this helps! :D

7 0

3 years ago

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

<em>Jayden's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

Need help asap !! i’ll mark brainly .

kirill [66]

Answer:

The last answer choice

Step-by-step explanation:

$2\dfrac{3}{5}$

$2+\dfrac{17}{15}$

$3\dfrac{2}{15}$

$b>3\dfrac{2}{15}$

The last answer choice is correct. Hope this helps!

7 0

3 years ago

Read 2 more answers

Eric purchased three music CDs and a sweatshirt from a band's online store and received a 20% discount. He paid $100 for his pur

emmasim [6.3K]

(3c+s)(100-20)/100=100 multiply both sides by 100

(3c+s)80=10000 divide both sides by 80

3c+s=125 subtract 3c from both sides...

s=125-3c....now let's look at the second situation...

(4c+2s)(100-40)/100=120 multiply both sides by 100

60(4c+2s)=12000 divide both sides by 60

4c+2s=200 divide both sides 2

2c+s=100 subtract 2c from both sides

s=100-2c, and from earlier we saw that s=125-3c, since s=s:

100-2c=125-3c add 3c to both sides

100+c=125 subtract 100 from both sides

c=25, and since s=100-2c

s=50

So cds cost $25.00 and sweatshirts cost $50.00

6 0

3 years ago

Read 2 more answers