What is -4(3x-2) + 5 = 73
1 answer:
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Given:
n = 50, sample size
, sample mean
s = 2.4 min, sample standard deviation.
The confidence interval is
At the 99% confidence level, t* (from the student's t-distribution) is
t* = 2.68
Therefore
t*(s/√n) = 2.68*(2.4/√50) = 0.9096
The confidence interval is
(23.6-0.9096, 23.6+0.9096) ≈ (22.69, 24.51)
Answer: (22.7, 24.5)
n = 50, sample size
s = 2.4 min, sample standard deviation.
The confidence interval is
At the 99% confidence level, t* (from the student's t-distribution) is
t* = 2.68
Therefore
t*(s/√n) = 2.68*(2.4/√50) = 0.9096
The confidence interval is
(23.6-0.9096, 23.6+0.9096) ≈ (22.69, 24.51)
Answer: (22.7, 24.5)
There are 2 tangent lines that pass through the point
and
Explanation:
Given:
The point-slope form of the equation of a line tells us that the form of the tangent lines must be:
For the lines to be tangent to the curve, we must substitute the first derivative of the curve for :
Substitute equation [2] into equation [1]:
Because the line must touch the curve, we may substitute
Solve for x:
±
±
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There are 2 tangent lines.
and