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2 years ago

The time it takes for an object stopped from a certain speed can be modeled by the equation

1 answer:

6 0

Given:
t = 1/2 √v
v = speed of object meters per second

t = 3 seconds

3 = 1/2 √v
3 * 2 = √v
6 = √v
6² = √v²
36 meters = v

v = 36 meters per second

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At the end of each year, how much money would you earn in interest if you invested $3,500 and earned 4.5% simple interest?

Stels [109]

$157.50 would be the amount that you earn in interest

7 0

3 years ago

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

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2 years ago

If you can drive 32 miles on one gallon of gas how many miles can you drive on 20 gallons?

Veseljchak [2.6K]

Answer:

640

Step-by-step explanation:

32 *20

4 0

2 years ago

A pet store has 150 goldfish and betta fish altogether. The ratio of goldfish to betta fish is 2:3. How many goldfish does the p

Kipish [7]

The number of goldfish in the pet store is equal to 60 fishes.

Let the goldfish be G.

Let the betta fish be B.

Given the following data:

Total number of fishes = 150 fishes.

Ratio of G to B = 2:3

Total ratio= 2 + 3 = 5

To calculate the number of goldfish that the pet store have:

<h3>What is ratio?</h3>

Ratio can be defined as an expression that is used to denote the proportion of two (2) or more quantities with respect to one another and the total quantities.

Mathematically, the number of goldfish in the pet store is given by this expression:

$G = \frac{2}{5} \times 150\\\\G=0.4 \times 150$