With exponents of 10, the exponent really just tells you how many zeroes there are behind the 1. So, for example, 10^4=10000 (4 zeroes behind 1). When multiplying decimals by exponents of 10, you move the decimal to the right, and the amount of places is the exponent number. For example, if I multiply 5.34 by 10^2, I move the decimal over to the right 2 times and get 534.
So, if you just multiply these you get 9.36*10000, which is 93600.
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
By pulling out the common factors for each pair of terms, we can rewrite the original polynomial like this:
3x(2x + 1) + 10(2x + 1)
These two terms now have a common factor of (2x + 1). Seems like we should be able to do something with that information, don't you think? In fact, we can pull out this common factor and rewrite the polynomial again:
If we will roll a fair die then the outcomes wil be 1,2,3,4,5,6.
Hence, the total number of events= 6
3,4,5 and 6 are greater than 2.
So, there's 4 events which are greater than 2.
Now the formula to find the probability is:
probability=
=
=
So, the probability of getting greater than a 2 is 2/3.
S = 2 (lw + lh + hw)
S = 2 ((8.5)(11) + (8.5)(2) + (11)(2))
S = 2 (93.5 + 17 + 22)
S = 2 (132.5)
S = 265 sq in
