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Bess [88]
3 years ago
11

A snail moves at a speed of 2.394 inches per minute. If the snail keeps moving like this how much will it travel in 7.489 minute

s
Mathematics
1 answer:
svetlana [45]3 years ago
4 0
1. write function

2.394 in. / 1 minute × #of minutes = #of ft traveled
2.394 × x = y

2. insert value for x

2.394 × 7.489 = y
2.394 × 7.489 = 17.296
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Step-by-step explanation:


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If m<ECD is six less than five times m<BCE. and m<BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

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∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

  angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

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What is the surface area of the prism?
Sever21 [200]

Answer:

Question 3: 582 ft²

Question 4: 348 in²

Step-by-step Explanation:

Question 3:

Consider the solid shape given as being consisting of two rectangular prism. With careful examination, you'd observe that the offer one beneath has dimensions, l, w, h, as 15, 4, 9

The second one has l, w, h, as 6, 4, 6

Surface area of the bigger rectangular prism = total surface area - area of the surface that is joined to the smaller rectangular prism.

Area of the face joined to the smaller rectangular prism = 4*6 = 24 ft²

Surface area of the bigger rectangular prism = 2(wl + hl + hw)  - 24

2(4*15 + 9*15 + 9*4)  - 24

462  - 24

Surface area of the bigger rectangular prism = 438 ft²

Surface area of the smaller rectangular prism = total surface area of rectangular prism - area of the surface that is joined to the bigger rectangular prism.

= 2(wl + hl + hw)  - 24

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= 168 - 24 = 144 ft^2

<em><u>Surface area of the solid = 438 + 144 = 582 ft²</u></em>

Question 4:

Surface area of the triangular prism is given as: 2(B.A) + P*L

Where,

B.A = area of 1 triangular base = ½*height of the triangle*base of the traingle

B.A = ½*6*16 = 3*16 = 48 in²

P = perimeter of 1 triangular base = sum of all sides of the triangle.

P = 16+10+10 = 36 in

L = length or height of prism =

Plug in the values to find surface area of the prism

Surface area = 2(B.A) + P*L

= 2(48) + 36*7 = 96 + 252 = 348 in²

<em><u>Surface area of prism = 348 in²</u></em>

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3 years ago
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