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Mashcka [7]
2 years ago
6

Solve pls brainliest

Mathematics
1 answer:
AnnZ [28]2 years ago
7 0

Answer:

anung grade yan?kasi may ibang ganyan

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Multiply Conjugates Using the Product of Conjugates Pattern
SpyIntel [72]

Answer:

The product is the difference of squares is $$\left(11-b\right)\left(11+b\right)=121-{{b}^2}$$

Step-by-step explanation:

Explanation

  • The given expression is (11-b)(11+b).
  • We have to multiply the given expression.
  • Square the first term 11. Square the last term b.

$$\begin{aligned}&(11-b)(11+b)=(11)^{2}-(b)^{2} \\&(11-b)(11+b)=121-b^{2}\end{aligned}$$

5 0
2 years ago
Evaluate the expresion<br> 27+6x2+3/6
SSSSS [86.1K]
Exact Form: \frac{79}{2}


Decimal Form: 39.5


Mixed Number Form: 39\frac{1}{2}
5 0
2 years ago
Solve the proportion 4/x=8/(x-3)
jenyasd209 [6]

Answer:

x=-3

Step-by-step explanation:

4/x=8/(x-3)

We can solve this using cross products

4 ( x-3) = 8x

Distribute

4x -12 = 8x

Subtract 4x from each side

4x-4x-12 = 8x-12-4x

-12 =4x

Divide each side by 4

-12/4 = 4x/4

-3 =x

4 0
3 years ago
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Applying One-Step Inequalities
sergij07 [2.7K]

Answer:

1). n </=6

2). n > 27.25

3). n > 10.50

8 0
3 years ago
A three-bedroom house in North Augusta sold for $190,000. If housing prices are expected to increase 1.8% annually in that town,
Ivahew [28]

Answer:

we know that the initial price of the house is $190,000.

We also know that the expected increase is 1.8%, this means that the year zero we have no increase; the price is $190,000.

one year after we have an increase of the 1.8% (or 0.018 in decimal form), this means that the new price is:

$190,000 + $190,000*0.018 = $190,000*(1.018)

another year after, we have:

$190,000*(1.018)*(1.018) = $190,000*(1.018)^2

and etc

The function that models the price as a function of the years, represented as y, is:

P(y) = $190,000*(1.018)^y

If we want to know the price in 5 years, we need to replace y = 5 in the equation:

p(5) = $190,000*(1.018)^5 = $207,726.80

Step-by-step explanation:

hope this helps you

3 0
3 years ago
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