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2 years ago

Here james and stuff i need this

Mathematics

1 answer:

Wittaler [7]2 years ago

4 0

Answer:

The Cost Price will be $19.99

Step-by-step explanation:

James

Sale Price = (100 - Discount Rate) x Cost Price

Let Y = Cost Price

By Putting the values in above equation:

$16.99 = (100 - 15) x Y

$16.99 = 0.85Y

Dividing the equation by 0.85, we get

Y = $16.99 / 0.85

Y = $19.99

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Solve the matrix equation below

Ket [755]

Answer:

We need to distribute the values
Hence [-4 0: 0 - 2 ] +[0 -3: 5 -4] X + [ 0 -3: 5 -4 ] = [19 -27 : 10 -24]

6 0

2 years ago

10. Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 3 liters of natural oil for every 4

jeyben [28]

you have the ratio of natural:synthetic so;

3:4

3+4=7

357/7=51

3*51:4°51

153:204

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i hope this helps you!!

7 0

2 years ago

Which value of n makes the equation true? 2/3n = -12

vivado [14]

Answer:

-1/18

Step-by-step explanation:

Let's multiply left and right by 3n:

2 = -12 * 3n =>

-36n = 2

now divide by -36:

n = 2/-36 = -1/18

5 0

2 years ago

Read 2 more answers

The variables x and y vary inversely. When y is 10, x is 10. What is x when y is 20

dezoksy [38]

inversely
y = k/x
k = yx
k = 10*10 = 100

when y = 20

20 = 100/x
20x = 100
x = 5

answer
 x = 5 when y is 20

8 0

3 years ago

) A watershed experiences a rainfall of 8 inches. What is the runoff volume when the curve number is 80

finlep [7]

Answer:

5.625 inches

Step-by-step explanation:

Given that:

Total Rainfall in inches (P) = 8 inches

The runoff volume (in inches) Q = ???

The curve number CN = 80

Recall that: The runoff volume can be calculated by using the formula:

$Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}$ for P > 0.2S

Q = 0 for P < 0.2S

$S = \dfrac{1000}{CN}-10$

where:

curve number CN = 80

$S = \dfrac{1000}{80}-10$

S = 2.5 inches

Since the rainfall (P) is greater than 0.25

Then:

$Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}$

$Q = \dfrac{(8-0.2(2.5))^2}{(8+0.8(2.5))}$

$Q = \dfrac{(8-0.5)^2}{(8+2)}$

$Q = \dfrac{(7.5)^2}{(10)}$

$Q = \dfrac{(56.25)}{(10)}$

Q = 5.625 inches

Thus, the runoff volume = 5.625 inches

4 0

3 years ago