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Bond [772]
3 years ago
9

Joseph reads 12 pages in 84 minutes. Assume Joseph reads at a constant speed. Write the number of minutes it takes Joseph to rea

d 1 page.
Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

I think 7

Step-by-step explanation:

84 divided by 12 is 7

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143 is added to twice a number and this sum is multiplied by 2, the result is the same as if the number is multiplied by 0 and 2
serious [3.7K]

Answer:

-71

Step-by-step explanation:

let 'n' = a number

2(143 + 2n) = 0n + 2

2(143 + 2n) = 2

143 + 2n = 1

2n = -142

n = -71

5 0
2 years ago
What is the value of f in f/12.7= 15.26
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F is 198.374 hoped i helped
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4x-3 (x-2y) + 1/2 (6x-8y)
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4x+2y i hope that helps :3
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A group of 6 friends decides to rent a vacation house for a month. The monthly rent on the house is $2,130. Each friend pays an
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The amount each friend pays=2130/6=$355
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3 years ago
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13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that \frac{ab}{m} is and integer.

As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

So \frac{ab}{m}v=\frac{ab}{m}\frac{m}{b}=a, so \frac{ab}{m} divides a; on the other hand, \frac{ab}{m}u=\frac{ab}{m}\frac{m}{a}=b, so \frac{ab}{m} divides b. From this we can conclude that \frac{ab}{m} is a common divisor of a and b.

4 0
3 years ago
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