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marishachu [46]
1 year ago
13

I got 8 mm and 2mm rectangle. what is the perimeter?the area is 16

Mathematics
1 answer:
Scorpion4ik [409]1 year ago
5 0

Let length, l=8 mm.

Braedth, b=2 mm.

The perimeter of the rectangle is,

\begin{gathered} P=2(l+b) \\ P=2(8+2) \\ P=2\times10 \\ P=20mm^2 \end{gathered}

Therefore, the perimeter of the rectangle is 20 mm^2.

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B) 75: 125 help me solve it
mash [69]

75:125

divide both sides by 25

75/25= 3

125/25= 5

Answer: 3:5

4 0
3 years ago
Write the equation of a hyperbola with vertices (0, -4) and (0, 4) and foci (0, -5) and (0, 5).
andre [41]
Check the picture below.  So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{{{ a }}^2+{{ b }}^2}
\end{cases}\\\\
-------------------------------\\\\

\bf \begin{cases}
h=0\\
k=0\\
a=4\\
c=5
\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1
\\\\\\
c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\\\\\\
\sqrt{5^2-4^2}=b\implies \boxed{3=b}
\\\\\\
\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}

7 0
3 years ago
Give three numbers whose product is -64
ololo11 [35]

Answer:

8 times -8

2 times -32

4 times -16

Step-by-step explanation:

hopefully that helped

8 0
3 years ago
Read 2 more answers
Jordan bought 7.06 meters of rope.What is the word name?
dexar [7]

seven ones and 6 hundredths

I hope this helps you

3 0
2 years ago
Your help is greatly appreciated. Need help please.
ehidna [41]

Answer:

  $13.00

Step-by-step explanation:

Let f represent the price per foot of pasture fence, and p represent the price per foot of picket fence. The two purchases can be written in equation form as ...

  2000f + 450p = 12850

  700f +300p = 6350

Using Cramer's rule, we can find the value of the picket fence as ...

  p = (12850·700 -6350·2000)/(450·700 -300·2000) = -3705000/-285000

  p = 13

The cost per foot of picket fence is $13.00.

_____

<em>Cramer's Rule and Vedic math</em>

The above equation for p is a summary of the math you would be doing if you were to solve the equations by eliminating f. Cramer formulates it in terms of determinants of the coefficients in the equations. Practitioners of Vedic math formulate it in terms of X-pattern combinations of the coefficients in much the same way as finding a determinant. For the equations ...

  • ax +by = c
  • dx +ey = f

The solutions are ...

  ∆ = bd -ea

  x = (bf -ec)/∆

  y = (cd -fa)/∆ . . . . . this is the equation we used above

__

If you do a rigorous comparison of this formula with that of Cramer's rule, you find the signs of numerator and denominator are reversed. That has no net effect on the solution, but it makes the X pattern of products easier to remember for practitioners of Vedic math.

6 0
3 years ago
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