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Stolb23 [73]
2 years ago
14

Which list contains values that are all part of the solution set of the graphed inequality? 2, 1, 3. 9, 4 2001. 3, 4, 0, 2. 6 1.

1, 1. 5, 19. 7, 8. 2 11, 1, 48. 5, 7.
Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
8 0

The inequality is,

0\leq x\leq 2001.3

we have given that the solution set

2, 1, 3. 9, 4 2001. 3, 4, 0, 2. 6 1. 1, 1. 5, 19. 7, 8. 2 11, 1, 48. 5, 7.

here we have given that all the values of x are positive and

Which is the smallest point in above set?

0

and

Which is the highest point in the above set?

2001.3

Therefore,

we have a=0 and b=2001.2

Our equality lie in a and b

Therefore,

a\leq x\leq b

Plug the value of a and b we get

0\leq x\leq 2001.3

Therefore we get the inequality is,

0\leq x\leq 2001.3

To learn more about the inequality visit:

brainly.com/question/24372553

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Mrs. Tomas is installing a fence around the perimeter of her garden. The perimeter of the garden is 36 feet. Each section of the
WITCHER [35]

Answer:

C = (36/3)* $24

C = $288

Step-by-step explanation:

In this question, we are asked to write an equation for cost c of the section of fence needed for the garden and the solve for the value c.

C is already assigned as the cost of the sections she needs for her garden.

We were made to understand that the perimeter of the garden is 36 feet, with a 3 feet each section. Now, what we need to do is to know the number of sections that we have. Since, each section is 3 feet, and the total perimeter is 36 feet, this means that the total number of sections needed would be 36/3. Each of the section as we were told costs $24, so we can then proceed to calculate the value of C from there.

C = (36/3)* $24

This is the equation that gives the cost. The actual value of the cost is thus:

C = 12 * 24 = $288

The total cost of the sections if the Fence is $288

8 0
3 years ago
(-2/3)^7*(3/5)^6*(5/6)^5*(1/3)^-7 simplify of law of indices ​
Wewaii [24]

Answer:

\boxed {-\frac{12}{5}}

Step-by-step explanation:

Solve the following expression:

(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Calculate -\frac{2}{3} to the power of 7:

(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Calculate \frac{3}{5} to the power of 6:

-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Multiply both -\frac{128}{2187} and \frac{729}{15625}:

-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Calculate \frac{5}{6} to the power of 5:

-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}

-Multiply both -\frac{128}{46875} and \frac{3125}{7776}:

-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}

-\frac{4}{3645} \times (\frac{1}{3})^{-7}

-Calculate \frac{1}{3} to the power of -7:

-\frac{4}{3645} \times (\frac{1}{3})^{-7}

-\frac{4}{3645} \times 2181

-Multiply both the -\frac{4}{3645} and 2187:

-\frac{4}{3645} \times 2181

\boxed {-\frac{12}{5}}

Therefore, the final answer is -\frac{12}{5}.

3 0
3 years ago
Mrs. Douglas packs candy bars into boxes for the members of the school band to sell as a fundraiser. Each candy bar weighs 5.75
olchik [2.2K]

Answer:

d

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A closed cylindrical tank had a diameter and height 7m what is the capacity of the tank
bezimeni [28]

Area of a cylinder is pi*r^2*h

The radius is half the diameter.

So the radius is 3.5

3.14*3.5^2*7=269.255 cubic meters.

3 0
3 years ago
Determine if the lines are parallel, perpendicular, or neither 10x+5y=-5 and y=-2x+6
Ksenya-84 [330]
If they are parallel they will have the same slope , m

So in y = mx + c, if there are two equations which both have the same m value they will be parallel.
If the lines are perpendicular they'll have slopes like this: 1/2 to -2/1 - where they flip and a negative gets added.

In the equations: 10x + 5y = -5 , and y = -2x + 6
We can rearrange 10x + 5y = -5 to be in the form y = mx + c
10x + 5y = -5
5y = -5 - 10x
y = -1 - 2x
y = -2x - 1

Since y = -2x - 1 and y = -2x + 6 both have the same slope of -2 they are parallel!

7 0
3 years ago
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