3 years ago

A more reactive metal displaces a less reactive metal from salt solution. Such reactions are called:

Chemistry

2 answers:

faust18 [17]3 years ago

8 0

Answer:

displacement reaction

motikmotik3 years ago

6 0

Answer:

Displacement Reaction.

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$E(4)=\frac{13.6}{4^2}=\frac{13.6}{16}\\ \\E(1)=\frac{13.6}{1^2}=\frac{13.6}{1}\\ \\The\ ratio\ of\ their\ ionization\ energy=\frac{E(4)}{E(1)} =\frac{\frac{13.6}{16} }{\frac{13.6}{1} } =\frac{1}{16}=1:16$

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3 years ago

If the number is not a proper coefficient, how would you make it one?

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I’m pretty sure you add, multiply, subtract, & divide

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1 year ago

In this equation, what should be the coefficients of the reactants and products?

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hope this helps!

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