Question

Under ideal conditions each NADH molecule will result in three ATP molecules, and each FADH2 molecule will result in two ATP molecules during oxidative phosphorylation. Calculate the total number of ATP molecules that might be produced in this phase of cellular respiration from one glucose molecule.

Answer 1

Answer: 38ATP

Explanation:

In the glycolytic pathway, metabolism of one molecule of glucose will produce

Step 1. 1 ATP loss= -1ATP

Step 2. 1 ATP loss= -1ATP

Step 5. 2 NADH gain = 3*2=6ATP

Step 6. 2 ATP gain = 1*2=2ATP

Step 9. 2 ATP gain= 1*2=2ATP

Pyruvate to acetyl CoA. 2 NADH gain =3*2=6ATP

TCA Cylce

Step 3. 2 NADH gain=3*2=6ATP

Step 4. 2 NADH gain=3*2=6ATP

Step 5. 2 GTP gain=1*2=2ATP

Step 6. 2 FADH2 gain=2*2=4ATP

Step 8. 2 NADH gain=3*2=6ATP

Net ATP gain in glycolysis 10-2=8ATP

Pyruvate DH reaction = 6 ATP

TCA =24

Net ATP generated from one molecule of glucose =38 ATP