For this case as MNOP is a square then the angles of each vertex are equal to 90 degrees.
Therefore, we have the following equations:
From these equations, we can clear the values of the unknowns.
For equation 1 we have:
For equation 2 we have:
Answer:
The values of t and f are given by:
Density = Mass / Volume = 2000/0.5
Density = 4000 Kg/m^3
Answer:
In parallelogram ABCD
FD is perpendicular to BC
BE is perpendicular to CD
Consider triangle BEC and triangle DFC
FC = EC (Given)
Angle BEC = Angle DFC (=90°)
Angle BCE = Angle DCF (common)
Therefore triangle BEC is congruent to triangle DFC (AAS congruency)
DF = BE (CPCT)
Since the altitudes are equal their bases will also be equal
Therefore BC = DC
Therefore BC = DC = AD = AB
Therefore ABCD is a rhombus
Hope this helps!
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ANSWER
True
EXPLANATION
The given trigonometric equation is:
We take the LHS and simplify to arrive at the RHS.
Collect LCM on the right hand side to get;
This implies that
This identity has been verified .Therefore the correct answer is true.
