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Wewaii [24]
3 years ago
10

Determine whether the Mean Value Theorem applies to the function f(x)=2x^1/5 on the interval [-32, 32]

Mathematics
1 answer:
Anettt [7]3 years ago
5 0

Answer

given,

f(x) = 2 x^{1/5}

interval = [-32, 32]        

differentiating the given equation

f'(x) = \dfrac{d}{dx}(2 x^{1/5})

f'(x) = \dfrac{2}{5x^{4/5}}

hence, the above solution is not defined at x = 0

and x = 0 lie in the given interval i.e. [-32, 32]

so, at x = 0 the function is not differentiable.

Hence, mean value theorem does not apply to the given function.

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What is the cofunction of cos 2pi/ 9
fiasKO [112]

The cofunction of cos is sin(90-x)

90 degrees is equal to PI/2

The cofunction becomes sin(PI/2 - 2PI/9)

Rewrite both fractions to have a common denominator:

PI/2 = 9PI/18

2PI/9 = 4PI/18

Now you have sin(9PI/18 - 4PI/18)

Simplify:

Sin(5PI/18)

3 0
3 years ago
A cone with volume 246 ft cubic if the height is 15 find the radius
Liula [17]

Answer:

r = 3.95 ft

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h = 246 ft³

246 = \frac{1}{3} * \frac{22}{7} * r^2 * 15

r² = \frac{246*3*7}{22*15*5}

r = \sqrt{15.65}

r = 3.95 ft

8 0
3 years ago
Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She
andreyandreev [35.5K]

Answer:

3w+45=557

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

w+33 kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

w+12 kg.

The total weight of all boxes is

w+(w+33)+(w+12)=w+w+33+w+12=3w+45 kg

Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

3w+45=557

or

3w=512

3 0
3 years ago
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Reptile [31]

Answer:

0.5

Step-by-step explanation:

0.5 x 4 = 2, 2 + 7 = 9

4 0
3 years ago
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Answer:

A

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4 0
3 years ago
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