Answer
given,
interval = [-32, 32]
differentiating the given equation
hence, the above solution is not defined at x = 0
and x = 0 lie in the given interval i.e. [-32, 32]
so, at x = 0 the function is not differentiable.
Hence, mean value theorem does not apply to the given function.
Answer:
65
Step-by-step explanation:
Use the law of sines.
Plug values in.
Cross multiply.
Hope that helps.
X=15
Answer: Dunno I'm lazy lol T-T
Step-by-step explanation: 123