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Wewaii [24]
3 years ago
10

Determine whether the Mean Value Theorem applies to the function f(x)=2x^1/5 on the interval [-32, 32]

Mathematics
1 answer:
Anettt [7]3 years ago
5 0

Answer

given,

f(x) = 2 x^{1/5}

interval = [-32, 32]        

differentiating the given equation

f'(x) = \dfrac{d}{dx}(2 x^{1/5})

f'(x) = \dfrac{2}{5x^{4/5}}

hence, the above solution is not defined at x = 0

and x = 0 lie in the given interval i.e. [-32, 32]

so, at x = 0 the function is not differentiable.

Hence, mean value theorem does not apply to the given function.

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Consider the system of equations
Free_Kalibri [48]

Answer:

(-3,-8)

Step-by-step explanation:

okay so what we can do here is elimination

we can do this first by multiplying the entire second equation by 2

so then it would become

2(5x-2y=1)

10x-4y=2

now we can add the two equations together which will eliminate y

so

-8x+4y=-8 plus

10x-4y=2 equals

2x=-6

we did that by combining like terms

next we can simplify that

x=-3

now we can plug that into the equation

-8(-3)+4y=-8

simplify

24+4y=-8

4y=-32

y=-8

our answer would be

(-3,-8)

7 0
3 years ago
Read 2 more answers
Please help me with this homework
4vir4ik [10]
The answer is 1.25.

The equation for slope is rise over run. Y is the rise and X is the run. The point equation is (y2-y1)/(x2-x-1) = slope.

Plugging in the numbers: (-4-1)/(-4-0) = 1.25
6 0
2 years ago
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Math pls help dhsjdjdjdj​
Aleks [24]

Answer:

2350 is 88.68% of 2650.

Step-by-step explanation:

2350/2650

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6 0
3 years ago
Find the mean and mode for this set of data. 5,6,8,3,5,7,4,11,5,7
katrin [286]

The mode is what number occurs most often. So in this set, the number that occurs most often is 5.

Mode = 5

The mean is the average of all the numbers in the set. To find the average of numbers, you add them all up then divide by how many numbers there are in the set. 5 + 6 + 8 + 3 + 5 + 7 + 4 + 11 + 5 + 7 = 61. 61 divided by 10 = 6.1 The answer is 6.1

Mean = 6.1

Good luck, my guy!

3 0
3 years ago
Read 2 more answers
HELP PLZ
Artyom0805 [142]

Answer:

In this question you got multipel answers.

If she buys as much pants as she can;

135 - (15.p) = 5.s

135 - (15.9) = 0

so now she has bought no shirts and 9 pants.

if she buys as much shirts as she can;

135 - (5.s) = 15.p

135 - (5.27) = 0

so now she has bought no pants and 27 shirts.

If she wants a shirt for each pants the equation would look something like this;

p=s=x

135 - (15.x) = 5.x

but with each pants she can buy three shirts, so 9 = 3.3

(7.15)+(6.5)= 105+30= 135

so now she has 7 pants and 6 shirts.

7 0
3 years ago
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