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Mrrafil [7]
4 years ago
15

The length of a rectangle is three times it’s width. The area of the rectangle is 48 square centimeters. Find the measures of th

e sides.
Mathematics
1 answer:
denis-greek [22]4 years ago
7 0
---------------------------------------------------------------------------------
Define length and width
---------------------------------------------------------------------------------
Let the width be x
Width = x
Length = 3x

---------------------------------------------------------------------------------
Form equation and solve for x
---------------------------------------------------------------------------------
x(3x) = 48
3x² = 48
x² = 48 ÷ 3
x² = 16
x = √16
x = 4

---------------------------------------------------------------------------------
Find length and width
---------------------------------------------------------------------------------
Width = x = 4
Length = 3x = 3(4) = 12

---------------------------------------------------------------------------------
Answer: Width = 4cm, Length = 12cm
---------------------------------------------------------------------------------
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You can divide the figure as follows:

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  • A horizontal rectangle, 2 meters tall and 5 meters wide, on the bottom left
  • A 2x2 meters square on the bottom right, where the two rectangles meet.

The area of the rectangles is 5x2=10 meters squared, while the area of the square is 2x2=4 meters squared.

So, the total area is 10+4=14 meters squared.

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4 years ago
Apply the distributive property to create an equivalent expression. (1-2g+4h)x5
kifflom [539]

Answer: 5-10g+20h

Step-by-step explanation:

You can rewrite as 5(1-2g+4h). 5x1 equals 5, 5x2g=10g, 5x4h=20h, then you get 5-10g+20h

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Using {0,1,3,4,5,6,9}, how many four-digit numbers with different digits can be produced between 4000 to 5000, if the numbers mu
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3 years ago
Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)
Gnom [1K]

Answer: Horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

Step-by-step explanation:

Since we have given that

y=\dfrac{x^2-9}{4x^2+1}

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is 4x^2+1

Now,

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And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

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8 0
3 years ago
PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!
disa [49]

Answer:

C. 15 votes

Step-by-step explanation:

B= votes Billy got

K = votes Keeton got

B = 3K


B+K =20

Substitute the first equation into the second equation

3K + K =20

Combine like terms

4K =20

Divide both sides by 4

4K/4 = 20/4

K =5

Keeton got 5 votes

B = 3*K

B = 3*5

B = 15 votes

Billy got 15 votes

3 0
3 years ago
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