If sec a = 5/4 and a is an angle in quadrant iv find the value of cos a
1 answer:
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Answer:
A) (-1,3) and (4,3)
B) (-1,-7) and (4,-7)
C) (1.5, .5) and (1.5, -4.5)
Step-by-step explanation:
For 1 and 2, because the y-values of the points are the same, the length of the square can be found by subtracting the x-coordinates.
4-(-1)=4+1=5
The length of the side of the square is 5.
1. For the first set of points, the square is above the two given points so just add 5 to the y-values
-2+5=3
This gives you the points:
(-1,3) and (4,3)
2. For the second set of points, the square is below the two given points so subtract 5 from the y-values.
-2-5=-7
This give you the points:
(-1,-7) and (4,-7)
3. The third answer is when the two given points are on opposite corners
of the square.
Here the diagonal is equal to 5 since they are on opposite corners of the square.
The diagonal of a square can be found with the pythagorean theorem
Since we have the diagonal we can find the side lengths we need.
s=
s=3.5355
We want the new vertices to be in the middle of the other vertices x-coordinates
The new vertices will be 2.5 units away from the other vertices
-1+2.5=1.5
The new vertices will be at x=1.5
Now we need the pythagorean theorem again to find the y-values
h=2.5
The new vertices will be:
(1.5, -2+2.5)=(1., .5)
(1.5, -2-2.5)=(1.5, -4.5)