According to the fundamental theorem of algebra, how many zeros does the polynomial below have?
2 answers:
<h2>Answer:</h2>
The given polynomial has 4 roots.
( may not be all distinct)
<h2>Step-by-step explanation:</h2><u>Fundamental Theorem of Algebra --</u>
It states that every non-constant polynomial of degree n has exactly n roots counting multiplicity.
i.e. the roots may repeat.
i.e. the number of roots of a non-constant polynomial of degree n has atmost n distinct roots.
We are given a polynomial as:
Clearly the polynomial is of degree 4.
This means that the roots of this polynomial will be: 4
( not all roots may be distinct)
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You mean y = b^x.
By plugging different values of x, we find different y-values forming points in the form (x, y).
After 2 or 3 points, we can clearly see that the graph of y = b^x passes through the point (0, 1) and extends forever in the upward direction through quadrant 1.
By plugging different values of x, we find different y-values forming points in the form (x, y).
After 2 or 3 points, we can clearly see that the graph of y = b^x passes through the point (0, 1) and extends forever in the upward direction through quadrant 1.
Formula used: cos(x) =
Hope this helped!
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