Establish two right triangles, both with the height of the pole, h.
Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.
Apply Pytagora's equation to both triangles.
1) h^2 = 7^2 - x^2
2) h^2 = 8^2 - (6-x)^2
Eaual 1 to 2
7^2 - x^2 = 8^2 - 6^2 +12x -x^2
12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21
x = 1.75
Substitue x-value in 1
h^2 = 49 - (1.75)^2 = 45.94
h = sqrt(45.94) = 6.78
Answer: option d.
Answer:
its c
Step-by-step explanation:
i think im sorry if it wrong this a unusal term for operation
<h2>
Answer: <u><em>
1</em></u></h2>
<u />
Step-by-step explanation:
![\sqrt[4]{81} -2\\=3-2 \\=1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D%20-2%5C%5C%3D3-2%20%5C%5C%3D1)