A manager wants to test whether two normally distributed and independent populations have equal variances. the appropriate test statistic for this test is a "F-statistics."
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What is F-statistics?</h3>
An F statistic is a value obtained after performing an ANOVA test or even a regression analysis to determine whether the means of two populations differ significantly.
Some key features regarding the F-statistics are-
- It is comparable to a T statistic from the a T-Test; a T-test would then inform you when a single result is statistically significant, whereas a F test would then tell you if a set of variables is statistically significant.
- When determining whether your total results are significant, you must use the F statistic in conjunction with the p value. Why?
- A significant result does not imply that all of your variables have been significant.
- The statistic is simply comparing the cumulative influence of all the variables.
To know more about the F-statistics, here
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Its a square. its the ultimate shape. :)
Where’s the figure at there’s only the questions
Answer:
C) 15
Step-by-step explanation:
Here we have to use the combination to find the number of possible combinations.
Total number of classmates (n) = 6
We are selecting 2 individuals. So r = 2.
The combination formula nCr = ![\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Plug in n = 6 and r =2, in the above formula, we get
= ![\frac{6!}{2!(6-2)!}](https://tex.z-dn.net/?f=%5Cfrac%7B6%21%7D%7B2%21%286-2%29%21%7D)
= ![\frac{6!}{2!4!}](https://tex.z-dn.net/?f=%5Cfrac%7B6%21%7D%7B2%214%21%7D)
Simplifying the above factorial, we get
= 15
So the answer is C) 15