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Vinvika [58]
4 years ago
11

How do I solve ln(3x-5)=ln11+ln12

Mathematics
1 answer:
vladimir2022 [97]4 years ago
3 0

Answer:

\large\boxed{x=\dfrac{137}{3}}

Step-by-step explanation:

\text{Use:}\\\\\ln a+\ln b=\ln(ab)\\\\\ln a=\ln b\Rightarrow a=b\\-------------\\Domain:\\\\3x-5>0\qquad\text{add 5 to both sides}\\\\3x>5\qquad\text{divide both sides by 3}\\\\x>\dfrac{5}{3}\\-----------------\\\\\ln(3x-5)=\n11+\ln12\\\\\ln(3x-5)=\ln(11\cdot12)\\\\\ln(3x-5)=132\iff3x-5=132\qquad\text{add 5 to both sides}\\\\3x=137\qquad\text{divide both sides by 3}\\\\x=\dfrac{137}{3}

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Answer:
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Explanation:
To answer the question, we will simply multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final expression.

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answer

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step by step answer :

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