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charle [14.2K]
4 years ago
15

There are 900 toothpicks in a​ regular-sized box. If a jumbo box is made by tripling all the dimensions of the​ regular-sized bo

x, how many toothpicks will the jumbo box​ hold?
Mathematics
2 answers:
Colt1911 [192]4 years ago
6 0

When you triple the height of the box, it can hold (900 x 3) = 2,700 pieces.

Then triple its length, and it can hold (2,700 x 3) = 8,100 pieces.

Then triple its width, and it can hold (8,100 x 3) = 24,300 pieces.

When you triple the dimensions of a 3D object, it has 27 times its original volume.  (900 x 27) = 24,300 .

Vaselesa [24]4 years ago
4 0

Answer: 24300 toothpicks

Step-by-step explanation:

The volume of the box can be written as:

V0 = W*L*H

where W is the width, L is the length and H is the height.

We know that in V0 we can put 900 toothpicks.

Now, if we triply each of the dimensions we have that:

V = 3W*3L*3H = (3*3*3)*W*L*H

and we know that W*L*H = V0

V = 27*V0

and if in V0 we can put 900 toothpicks, then in V we can put 27 times that amount, this is:

27*900 = 24300 toothpicks

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Read 2 more answers
2x + 4y + z = 3<br> x − 2y − 3z = 4<br> x + y − z = −1
ozzi
<span>A) 2x + 4y + z = 3
B) x − 2y − 3z = 4
C) x + y − z = −1

Multiplying B & C by -1
</span>
<span>B) -x + 2y + 3z = -4
C) -x - y + z = +1 Then adding to A
</span><span>A) 2x + 4y + z = 3
5y + 5z = 0
So basically z = -y

</span><span>A) 2x + 4y -y = 3
B) x − 2y + 3y = 4
C) x + y +y = −1
</span><span>
A) 2x + 3y = 3</span>

Multiplyig B by -2
B) -2x -2y= -8
<span>C) x + 2y = −1 Adding B&C
-x = -9
x = 9

</span>
A) 2*9 + 4y + z = 3
A) 4y + z = -15
B) 9 − 2y − 3z = 4
<span>B) − 2y − 3z = -5

</span>A) 4y + z = -15
B) − 2y − 3z = -5
Multiplying A by 3
A) 12y + 3z = -45
B) − 2y − 3z = -5 Then adding A & B
10y = -50
y = -5

C) x + y − z = −1
C) 9 -5 − z = −1
<span>C)5  =z

</span>So x = 9
y= -5
z = 5

Wow!!!!!!!!!!!!



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Please help.<br> Algebra.
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Step-by-step explanation:

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