In the given question it is given that , AC = 105 yd, BC = 60 yd and angle ACB= 69.3 degree.
We have to find the distance of AB, and for that we use law of cosine, which is

Substituting the values of AC, BC and theta, we will get



HOW TO:
* use slope intercept form
1) find the slope
slope = rise/run (rise divided by the run)
slope = -4/2
slope = -2
2) find the y-intercept (just the point where the line intersects the y-axis)
y-intercept is (0,-4)
3) use slope-intercept form:
y = mx + b (m stands for the slope, b stands for the y-intercept)
y= -2x + (-4)
y= -2x - 4
So your equation is y= -2x-4
Its b because the equation pretty much says that is fx is gx when x is subtracted by 2
Answer:
26.25
Step-by-step explanation:
y = 8.75(3)
y = 26.25

Move the constant to the right-hand side and change its sign to minus sign since it is in plus

Subtract the numbers

Divide both sides of equation by 3

- On observing the above steps, Option B is correct!
- <em>First</em><em> </em><em>step</em><em> </em><em>is</em><em> </em><em>subtraction</em><em> </em><em>then</em><em> </em><em>division</em>