Well, the first ballon appears to be halfway to the second (the second being 300 meters from the ground) so the first, being at approximately 150 meters, both away from the ground and the balloon, would have to travel a further 150 meters.
46.3/1.5 = 30.87 or 1.5/46.3 = 0.034
Is that what your looking for??
Answer:
c: f(x) = 2(4^x)
Step-by-step explanation:
the table shows that the function is exponential rather than linear.
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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If g is the gallons of gas, and the truck holds up to 20 gallons, then g can be anything from 0 to 20.
If there is zero gallons of gas (g = 0) then the truck will travel zero miles because M(0) = 17(0) = 0.
The max miles depends on the max gallons of gas, so the miles possible with 20 gallons is M(20) = 17(20) = 340.
So, g ranges from 0 to 20 and M(g) ranges from 0 to 340.
Therefore your answer is the last option.
