Answer:
2
Step-by-step explanation:
To find the scale of dilation, you have to compare the ratio of the after transform with before transform according to the center of dilation. In this case, the center of dilation is Q so you have to compare QA' : QA. We know that QA= 1.25 and AA' is 1.25. The distance of QA' will be:
QA'= QA + AA'= 1.25 + 1.25 = 2.5
The scale factor will be:
scale factor= QA' : QA.= 2.5 : 1.25
scale factor= 2
Answer:
EQUILATERAL TRIANGLE = 3/27
![\frac{27}{3 = } 9](https://tex.z-dn.net/?f=%20%5Cfrac%7B27%7D%7B3%20%3D%20%7D%209)
<h2>SO THE ANS IS 9 .</h2>
I HOPE IT IS HELPFUL
The initial value is 21 and rate of change is 16 pages per week
<em><u>Solution:</u></em>
Given that After writing part of his novel, Thomas is now writing 16 pages per week
After 4 weeks, he has written 85 pages.
Given that assume the relationship to be linear
Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + c
y = mx + c
where "y" is the number of pages written after 4 weeks
x = 4 weeks and m = 16 pages
Therefore,
85 = 16(4) + c
85 = 64 + c
c = 85 - 64
c = 21
Therefore, initial value is 21 and rate of change is 16 pages per week
Answer:
254 cm² (to 3 s.f.)
Step-by-step explanation:
Area of shaded region
= area of large circle -area of smaller circle
![\boxed{area \: of \: circle = \pi {r}^{2} }](https://tex.z-dn.net/?f=%5Cboxed%7Barea%20%5C%3A%20of%20%5C%3A%20circle%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20%7D)
Radius of large circle= 15cm
Radius of smaller circle= 12cm
Area of shaded region
= π(15²) -π(12²)
= 225π -144π
= 81π
= 81(3.14)
= 254.34
= 254 cm² (3 s.f.)
Answer:
D
Step-by-step explanation:
Area of H = 25pi
Area of J = 225pi
225pi/25pi = 9