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sukhopar [10]
2 years ago
7

An adult ticket for a magic show costs $18. A children's ticket for the magic show costs $12.

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
6 0

Answer:

for adult tickets 90 and for children’s tickets 30

Step-by-step explanation:

because 90(18) = 1,620 and 30(12) is 360 and when you add up 1,620 + 360 you will get the total which is $1980

Also i just took the test on k12 and got it right and i hope this helps!

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17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8   when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0
3 years ago
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The gravitational force exerted by the planet Earth on a unit mass at a distance r from the center of the planet is:
jolli1 [7]

Answer:

Yes, F is a continuous function of r

Step-by-step explanation:

We are given that

When r<R

F(r)=\frac{GMr}{R^3}

r\geq R

F(r)=\frac{GM}{r^2}

Where M=Mass of the earth

R=Radius of earth

G=Gravitational constant

We have to find the function is continuous of r or not.

LHL

\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}

RHL

\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}

F(R)=\frac{GM}{R^2}

When a function is continuous at x=a

Then, LHL=RHL=f(a)

RHL==LHL=F(R)

Hence, the function is continuous of r.

8 0
3 years ago
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