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Y_Kistochka [10]
2 years ago
10

Write in plain language: d / 5 *

Mathematics
1 answer:
Mademuasel [1]2 years ago
3 0

Answer:

d over 5 or d divided by five

or an unknown number over or divided by 5

Step-by-step explanation:

You might be interested in
Find x if f(x) = 2x + 7 and f(x) = -1.<br> A.5<br> B.-4<br> C.-4
faltersainse [42]

Answer:

x = - 4

Step-by-step explanation:

Hi there !

 if f(x) = 2x + 7 and f(x) = -1 =>

2x + 7 = - 1

2x = - 1 - 7

2x = - 8

x = - 8 ÷ 2

x = - 4

Good luck !

5 0
3 years ago
Which of the following statements are true? Select all that apply
Murrr4er [49]
A,C,D is as an answer
4 0
3 years ago
The _______________ separates the region of rejection from the region of non rejection.
Alekssandra [29.7K]

Answer:

Critical Value

Step-by-step explanation:

The critical value separates the region of rejection from the region of non rejection.

We define critical values as:

  • Critical value helps us to give the decision rule for the rejection or acceptance of null hypothesis.
  • Critical value separates the acceptance region from the rejection region.
  • These are referred to as cut-off values that define regions where the test statistic is unlikely to lie.
  • The critical value depends on the kind of test being performed and the significance level.

6 0
3 years ago
4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
Two step equation<br><br> n - 5/2 =5
Verdich [7]

Answer:

Step-by-step explanation:

two step equation

n - 5/2 = 5

n = 5 + 5/2

n = 5 + 2.5

n = 7.5

-----------

check

7.5 - 5/2 = 5

7.5 - 2.5 = 5

5 = 5

the answer is good

3 0
1 year ago
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