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Alona [7]
3 years ago
6

What is the interquartile range of the data?   

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0

Answer:

the answer is 26

amosc @briahall0

Step-by-step explanation:

zysi [14]3 years ago
3 0
An interquartile range is finding the median of the first half of the data set, and the second half, then subtracting the first median from the second one. 

The median of the data set is..

<span>17, 18, 18, 20, 23, 25, 27, 27, 34, 38, 40, 46, 46, 62, 67 

Now we have to find the interquartile points.

</span>17, 18, 18, 20, 23, 25, 27, 27, 34, 38, 40, 46, 46, 62, 67 

The interquartile points are 20 and 46. So subtract:

46 - 20 = 26

The answer is 26. :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
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Select the correct answer from each drop-down menu. y = x2 + 2x − 1 y − 3x = 5 The pair of points representing the solution set
katen-ka-za [31]

ANSWER

(-2,-1)

(3,14)

EXPLANATION

The given system is

y =  {x}^{2}  + 2x - 1

y - 3x = 5

or

y = 3x + 5

Equate both of them:

{x}^{2}  + 2x - 1 = 3x + 5

This implies that,

{x}^{2}   - x - 6 = 0

(x - 3)(x + 2) = 0

x=-2 or x=3

When x=-2, y=y=3(-2)+5=-1

(-2,-1) is a solution.

When x=3 , y=3(3)+5=14

(3,14) is also a solution.

7 0
4 years ago
A procedure for using sample data to find the estimated regression equation is _____. Group of answer choices point estimation i
mr_godi [17]

<em>c. the least squares method. </em>

Regression equation:

In simple linear regression, the predicted value of the dependent variable is given by the equation = b0 + b1x. The values of b0 and b1 are calculated from the data so that the line = b0 + b1X minimizes the total sum of squared errors (error is the difference between the predicted value and the actual value of y).

Least squares method:

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Learn more about Regression Equation on:

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2 years ago
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igomit [66]

Answer:

4(x - 1) = 4x - 4

3x + 6 = 3(x + 2)

Step-by-step explanation:

The first equation is

5x - 1 = 5x + 1

We simplify to get;

- 1 = 1

This is not true, therefore this equation has no solution.

The second equation is

3x - 1 = 1 - 3x

Combine like terms:

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x =  \frac{1}{3}

This has a unique solution.

The 3rd equation is

7x - 2 = 2x - 7

Group similar terms:

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The 4th equation is :

4(x - 1) = 4x - 4

4x - 4= 4x - 4 \\ x = x

This is always true. The equation has infinite solution.

The 5th equation is:

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This also has infinite solution

The 6th equation is

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It has a unique solution.

8 0
4 years ago
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