Hello! So, the train travels 80 miles in an hour. 90 minutes is equivalent ot 1 ½ hours. In case you don't know, ½ of 80 is 40. To find the distance gone in 90 minutes, we can just add 80 and 40. 80 + 40 is 120. Another way to solve it is to multiply 80 by 1.5 and you would still get the same answer. There. The train will have gone 120 miles in 90 minutes.
The measure of angle A in the isosceles triangle ABC is equal to 120 degrees.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
In the triangle ABC, AB = BC = 8. Triangle ABC is an isosceles triangle and ∠B = ∠C = 30° (base angles are equal).
∠A + ∠B + ∠C = 180° (sum of angles in a triangle)
∠A + 30 + 30 = 180
∠A = 120°
The measure of angle A in the isosceles triangle ABC is equal to 120 degrees.
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Answer:
5(a+4)
Step-by-step explanation:
expression is equivalent to 5a+20
To get the equivalent expression we need to factor the given expression
5a+ 20
5a can be written as 5 * a
20 can be written as 5*2*2
WE can see that common factor is 5 for both 5a and 20
So GCF is 5
Now we factor out GCF 5
WE put 5 outside and write all the left of factors inside the parenthesis
5a +20
5 (a+2*2)
5(a+4)
Answer : 2/3 or 0 R 6
Step-by-step explanation:
hope it helps
Answer:
AC = 6.05 cm
Step-by-step explanation:
We can draw two different trapeziums with the information given.
The possible drawings of the trapezium ABCD are in the image attached.
In both trapeziums, the length of AC is the same, and we can calculate this length using the law of cosines in the triangle ABC:
AC^2 = AB^2 + BC^2 - 2 * AB * BC * cos(B)
AC^2 = 4.8^2 + 6.8^2 - 2 * 4.8 * 6.8 * cos(60)
AC^2 = 23.04 + 46.24 - 65.28 * 0.5
AC^2 = 36.64
AC = 6.05 cm