I think its unlike but im not positive.
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
You would need 12 16oz boxes of pasta
12×4=48
Answer:
<em><u>0.3846</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>decimal</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>38.46</u></em><em><u>/</u></em><em><u>100</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>38.46</u></em><em><u>%</u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>percentage</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>50</u></em><em><u>/</u></em><em><u>130</u></em>
Step-by-step explanation:
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