Answer:
Step-by-step explanation:
In general, given the function, f(x), its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.
The answer to this question is y' = 10x^2 + 6. You have to use the power rule to bring the exponent down as a coefficient and then reduce the exponent by 1. Do it for all the terms using the sum rule for derivatives (derivative of a sum of the sum of its derivatives).
-6, all of them are the absolute value of 6 or just 6, -6 isn't equivalent to 6.
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➷ Here are the steps to solving that problem:
(2x+1)^2
=(2x+1)(2x+1)
=(2x)(2x)+(2x)(1)+(1)(2x)+(1)(1)
=4x^2+2x+2x+1
=4x^2+4x+1
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➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
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