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3 years ago

Determines whether the line through the points

1 answer:

5 0

Find their gradients using the change in y coords divided by the change in x coords. once you have the gradients (or slopes), multiply them by eachother - if the product is (-1) then theyre perpdendicular, if not, they are either parallel or intersect at a point

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13 - (n • 6) = 50 Pls help what would be the equation

olya-2409 [2.1K]

Answer:

n=-17/3

Step-by-step explanation:

16-(n.6)=50

16-6n=50

-6n=34

n=34/-6

n=-17/3

5 0

2 years ago

Suppose Lin labels the books at a constant speed of s books per minute. There can be several equations written that represent th

Alla [95]

Answer:

$S = \frac{b}{m}$

Step-by-step explanation:

Given

$Speed = s$

Required

Determine the expression for s

The speed is calculated as:

$Speed = \frac{Number\ of\ books}{Time}$

Substitute S for speed

$S= \frac{Number\ of\ books}{Time}$

Let the number of books be b and the time be m.

The expression becomes

$S = \frac{b}{m}$

Hence, the expression for the scenario is:

$S = \frac{b}{m}$

4 0

2 years ago

Question

kondor19780726 [428]

Answer: r = 11

Step-by-step explanation:

We know that the point (-2, r) lies on the graph of:

2*x + y = 7.

Then, if we that point is on the graph of the equation, we can replace the values and we will have:

2*(-2) + r = 7

and now we solve this for r-

-4 + r = 7

r = 7 + 4 = 11

r = 11

6 0

2 years ago

A music company offers a loan to buy a drum set for $1500. The simple interest is 11.8% and the loan will be paid in equal month

Mrrafil [7]

Simple interest is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments. It is expressed as:

I = Prt

I = 1500(.118)(2) = 354

Total amount to pay = $1854
Monthly payment = $77.25

Hope this answers the question. Have a nice day.

3 0

3 years ago

If SAT scores are normally distributed with a mean of 1518 and a standard deviation of 325, find the probability that a randomly

aliya0001 [1]

Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575

Z = (X - x_bar)/sigma

Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18

From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714

P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316

The correct answer is C.

3 0

3 years ago