Question

Please help with this question

Answer 1

R + S = 98
128R + 286S = 20128

substitute

R = 50
S = 48

Answer 2

From the problem we now there were 98 passengers

let X = coach seats and Y equal sleeper car seats

so number of seats sold would be x + y = 98, which to solve for x can be rewritten as x = 98 -y
 we know coach seats cost 128 and  sleeper car seats cost 286

 so we would multiply the cost of the seat by the number of seats to get a total cost

so 128x = total coast for coach and 286 = total for sleeper cars

we  also know the total value is  20,128

so 128x + 286y = 20,128

replace x in that equation with the subtraction one from above:

128(98-y) + 286y = 20,128

now distribute the 1st part of the equation by multiplying 128 by 98 and by y

12,544 - 128y + 286y = 20,128

combine the like terms ( the two which have Y in them)
12,544 + 158y = 20,128

subtract 12,544 from both sides of the equation:

158y = 7584

divide both sides by 158 to solve for y

y = 7584 / 158 =  48

there were 48 sleeper car seats sold

and 98 - 48 = 50 coach seats sold