Answer:
s = height above ground
s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)
at t = 0
s = 60 (clearly :)
now when does it hit the bleak earth?
That is when s = 0
4.9 t^2 - 20 t -60 = 0
solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)
t = 6.09 or - 2.01
use t = 6.09
now to do the last part there are two obvious ways to get t at the peak
1. look for vertex of parabola
2. look for halfway between t = -2.01 and t = 6.09
I will do it the hard (11) waay by completing the square
4.9 t^2 - 20 t = -(s-60)
t^2 - 4.08 t = -.204 s + 12.2
t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16
(t-2.04)^2 = -.204(s-80.2)
so
top at 80.2 meters at t = 2.04 s
===============
quick check on time
should be average of 6.09 and -2.01
=4.08 /2 = 2.04 check
Answer:

Step-by-step explanation:
Slope intercept form: y = mx + b
Find slope:
m = (y₂ - y₁) / (x₂ - x₁)
= (-5 - (-4)) / (0 - 4)
= -1 / -4
= 1/4
Find y intercept using anyone of the given points and slope from above:
y = mx + b

b = -5
Now use the above slope and y intercept to create equation of a line:

Slope = -4/5
Jeremiah looses money every time he buys a ticket
hope this helped a little
Answer:
The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees
Step-by-step explanation:
4a) Given the following
Opposite side = 38cm (side facing the given angle)
Required
Adjacent and hypotenuse side
According to SOH CAH TOA

Next is to get the adjacent

Next is to get the missing
Since sum of angle in the triangle is 180degrees
32 + 90 + x = 180
122 + x = 180
x = 180 - 122
x = 58degrees
-4g is what I got if ur evaluating
If it’s something about slope I got -4