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Alja [10]
2 years ago
5

Triangles ABC and DEF are mathematically similar. CB 9 cm FE 13.5 cm The area of triangle ABC is 34 cm?. Calculate the area of t

riangle DEF.​

Mathematics
1 answer:
Sauron [17]2 years ago
3 0

Answer:

9=100%

13,5=x

x=13,5×100/9

x=150%

it increased by 50%

so 34/100×150

area of DEF is 51 cm2

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Hello,
Nookie1986 [14]

Answer:

s = height above ground

s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)

at t = 0

s = 60 (clearly :)

now when does it hit the bleak earth?

That is when s = 0

4.9 t^2 - 20 t -60 = 0

solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)

t = 6.09 or - 2.01

use t = 6.09

now to do the last part there are two obvious ways to get t at the peak

1. look for vertex of parabola

2. look for halfway between t = -2.01 and t = 6.09

I will do it the hard (11) waay by completing the square

4.9 t^2 - 20 t = -(s-60)

t^2 - 4.08 t = -.204 s + 12.2

t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16

(t-2.04)^2 = -.204(s-80.2)

so

top at 80.2 meters at t = 2.04 s

===============

quick check on time

should be average of 6.09 and -2.01

=4.08 /2 = 2.04 check

7 0
2 years ago
Read 2 more answers
Write the equation of a line in the given form.
Gnom [1K]

Answer:

y = \frac{1}{4}x - 5

Step-by-step explanation:

Slope intercept form: y = mx + b

Find slope:

m = (y₂ - y₁) / (x₂ - x₁)

   = (-5 - (-4)) / (0 - 4)

   = -1 / -4

   = 1/4

Find y intercept using anyone of the given points and slope from above:

y = mx + b

-5 = \frac{1}{4}(0) + b

b = -5

Now use the above slope and y intercept to create equation of a line:

y = \frac{1}{4}x - 5

3 0
3 years ago
1. What is the slope of the graph? (HINT: Pay close attention to what the x and y axes are counting by!) 2. What does the slope
lidiya [134]

Slope = -4/5

Jeremiah looses money every time he buys a ticket

hope this helped a little

6 0
3 years ago
4. Determine all unknown sides and angles to 1 decimal place.
Ksju [112]

Answer:

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees

Step-by-step explanation:

4a) Given the following

Opposite side = 38cm (side facing the given angle)

Required

Adjacent and hypotenuse side

According to SOH CAH TOA

tan \theta = \frac{opp}{hyp}\\tan 32=\frac{38}{hyp}\\hyp=\frac{38}{tan 32}\\hyp=\frac{38}{0.6249}\\hyp=  60.81cm

Next is to get the adjacent

Cos 32=\frac{adj}{60.81}\\adj=60.81cos32\\adj=60.81(0.8480)\\adj= 51.57cm

Next is to get the missing

Since sum of angle in the triangle is 180degrees

32 + 90 + x = 180

122 + x = 180

x = 180 - 122

x = 58degrees

7 0
3 years ago
Functions quiz on khan. G(-4)=
kherson [118]
-4g is what I got if ur evaluating
If it’s something about slope I got -4
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2 years ago
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