Answer: 0.185 gallons
Step-by-step explanation:
Divide 5/12 by 2 1/4
First convert the improper fraction to a proper fraction, 2 1/4 = 9/4
5/12 ÷ 9/4
= 5/12 × 4/9
= 5/27 = 0.185
Answer:
To figure out the common denominator for these fractions, I'll first need to factor that quadratic in the denominator on the right-hand side of the rational equation. This will also allow me to find the disallowed values for this equation. Factoring gives me:
x2 – 6x + 8 = (x – 4)(x – 2)
The factors of the quadratic on the right-hand side "just so happen" to be duplicates of the other denominators. This often happens in these exercises. (So often, in fact, that if you get completely different factors, you should probably go back and check your work.)
Step-by-step explanation:
Answer:
The 95% confidence interval for the difference between the Route B and Route A commuting times is -4.640279 < μ₁ - μ₂ <-1.359721
Step-by-step explanation:
Here we have the formula for the confidence interval of the difference between two means given as follows;
Where:
= Mean of Route A = 40
= Mean of Route B = 43
s₁ = Standard deviation of time to work for Route A = 3 minutes
s₂ = Standard deviation of time to work for Route B = 2 minutes
n₁ = Number of days taken through Route A = 20 days
n₂ = Number of days taken through Route B = 20 days
At 95% confidence level, and df = 20 - 1 = 19 we have;
= ±2.03452
Plugging in the values, we have;
, which gives the 95% confidence interval for the difference between the Route B and Route A commuting times as follows;
-4.640279 < μ₁ - μ₂ <-1.359721.
Answer:
21; the age of the teacher
Step-by-step explanation:
15+x/2=18
Estimate - I estimated in the 20's because it only averaged up a little bit
Started with 23 and kept going until i got to my answer
21
15+21/2
36/2
18
Please mark brainliest :)
9514 1404 393
Answer:
Step-by-step explanation:
There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.
Let m = 0i +1j +ak. Then we require ...
m·p = 0 = 0×1 +1×2 +a(-2) ⇒ 0 = 2 -2a ⇒ a = 1
m = 0i +1j +1k
__
Let n = 2i +0j +bk
n·p = 0 = 2×1 +0×2 +b(-2) ⇒ 2 -2b = 0 ⇒ b = 1
n = 2i +0j +1k
