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romanna [79]
3 years ago
10

Pea flowers may be purple (P) or white (p). Pea seeds may be round (R) or wrinkled (r). What proportion of the offspring from th

e cross PpRr × PpRr are expected to have white flowers and wrinkled seeds?
Mathematics
1 answer:
Rudiy273 years ago
8 0

Answer:

The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.

Step-by-step explanation:

The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present. 

When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.

Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:

Purple flowers with round seeds: 9/16

Purple flowers with wrinkled seeds: 3/16 

White flowers with round seeds: 3/16

White flowers with wrinkled seeds: 1/16

The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits. 

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Step-by-step explanation:

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7 0
3 years ago
PLZ PLZZZZ HELP ASAP!!!!! <br> Explain the error: 144x2 - 100 (12x + 10)(12x - 10) 2(6x + 5)(6x - 5)
iogann1982 [59]

9514 1404 393

Answer:

  a factor of 2 is shown, but 4 was factored out

Step-by-step explanation:

The difference of squares is factored as ...

  a² -b² = (a +b)(a -b)

Then the given difference of squares factors as ...

  144x² -100 = (12x)² -10² = (12x +10)(12x -10)

Each of these factors has a factor of 2 that can be factored out:

  = (2(6x +5))(2(6x -5))

  = (2·2)(6x +5)(6x -5)

  = 4(6x +5)(6x -5)

The first factor should be 4, not 2.

7 0
3 years ago
Carrie wished to build a rectangular dog run along theside of her garage. The garage will serve as one side of the fence. If she
Nat2105 [25]

Given:

Carrie has 180 ft of the fencing and wishes the fence to be 4times as long as it is wide.

To Find:

The area in square feet that the fencing encloses.

Answer:

The fence encloses 3600 sq ft.

Step-by-step explanation:

Let x denote the length of the dog run and y denote the width of the dog run.

Given that the garage wall serves as one side of the dog run, we are left with 3 other sides to instal the fence.

Carrie has 180ft of fencing with her, so the sum of the lengths of the 3 sides has to be equal to 180. We can represent this in the form of an equation as

x+y+y=180\\\\x+2y=180\\\\x=180-2y

We are also given that Carrie wishes the fence to be 4 times as long as it is wide.

So,

x=4y

Replacing this value into the first equation, we have

4y=180-2y\\\\&#10;6y=180\\\\&#10;y=30

Therefore,

x=(4)(30)=120

Thus, the length of the dog run is 120ft and the width is 30ft.

The area enclosed will be equal to the length multiplied with the width. So,

(120)(30)=3600

The fence encloses 3600 sq ft.


4 0
3 years ago
I need some help on this! i need my grade to go up
Kaylis [27]
3rd one I think tho it may not be accurate
4 0
2 years ago
Read 2 more answers
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