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3 years ago

D= 5/6 (F+G)..........solve for F. What is the solution?Sorry, I'm really bad at algebra, and I was just wondering if anybody co

uld help me.

Mathematics

1 answer:

IRISSAK [1]3 years ago

8 0

$D=\frac{5}{6(F+G)} \\ \\ 6(F+G)= \frac{5}{D} \\ \\ F+G=\frac{\frac{5}{D}}{6}= \frac{5}{D}* \frac{1}{6} \\ \\ F+G= \frac{5}{6D} \\ \\ \boxed{F=\frac{5}{6D}-G}$

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3 years ago

Add or Subtract to Simplify:<br> (x5 + x3) - (6x - x3 + 6x5)

ziro4ka [17]

Answer:

$\boxed{ \bold{ \boxed{ \sf{ - 5 {x}^{5} + 2 {x}^{3} - 6x}}}}$

Step-by-step explanation:

$\sf{( {x}^{5} + {x}^{3} ) - (6x - {x}^{3} + 6 {x}^{5}) }$

When there is a ( - ) in front of an expression in parentheses , change the sign of each term.

Also, remove the parentheses

⇒ $\sf{ {x}^{5} + {x}^{3} - 6x + {x}^{3} - 6 {x}^{5} }$

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3 0

3 years ago

The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of

julia-pushkina [17]

Answer:

$180.4~cm^2$

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

$A=2\pi rh$

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

$A=2\pi rh+2\pi r^2$

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

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$A_o= 0.8*8.5=6.8~cm^2$