Answer:
The 3rd set
Step-by-step explanation:
The first set has a range of 6, not 5
The second set has a range of 5, but not a mean of 5
The third set has both a mean and a range of 5
<h2>
Answer with explanation:</h2>
Let
be the population mean lifetime of circulated $1 bills.
By considering the given information , we have :-

Since the alternative hypotheses is two tailed so the test is a two tailed test.
We assume that the lifetime of circulated $1 bills is normally distributed.
Given : Sample size : n=50 , which is greater than 30 .
It means the sample is large so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


The p-value= 
Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.
Answer:
1. 3sqrt(2)
Choice C
2. 2sqrt(3)
Choice D
Step-by-step explanation:
1. sqrt(x+3)
sqrt(15+3)
sqrt(18)
sqrt(9*2)
sqrt(9)sqrt(2)
3sqrt(2)
Choice C
2. 6/sqrt(x)
6/sqrt(3)
no radicals in the denominator, multiply by 1 in the form of the radical
6/sqrt(3) * sqrt(3)/sqrt(3)
6sqrt(3)/ (sqrt(3)*sqrt(3))
6sqrt(3)/3
2sqrt(3)
Choice D
Answer:
Area ABCDE = 82 cm²
Step-by-step explanation:
ABCDE = ΔEAD + ΔDAC + ΔCAB
ABCDE = (12×5)/2 + (12×6)/2 + (8×4)/2 = 30+36+16 = 82
Answer:
3=6
4=8
5=10
6=12
graph 1
Step-by-step explanation: