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rosijanka [135]
3 years ago
5

F(x) = x2 - 5

Mathematics
2 answers:
Veronika [31]3 years ago
7 0
For x=2, substitute in F(x) to find y ---> 2^2-5 =-1 
for x=4 , F(4) = 4^2-5 = 11
for x=7 , F(7) = 7^2-5=44
The range is {-1, 11, 44} 
Olenka [21]3 years ago
5 0
Well the person before me got it correct. the answer is D I've taken the test
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Pachacha [2.7K]

Answer:

54

Step-by-step explanation:

8 0
3 years ago
∫(cosx) / (sin²x) dx
kirza4 [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822772

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}


Make the following substitution:

\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}


and then, the integral (i) becomes

=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}


Integrate it by applying the power rule:

\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}


Now, substitute back for u = sin x, so the result is given in terms of x:

\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}


\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0
4 years ago
Help quick Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k.
Salsk061 [2.6K]

Answer:

k = -3

Step-by-step explanation:

F(x) has a positive slope

g(x) has a negative slope

Let x = -3

The y value goes from 1 to -3

g(x) = k⋅f(x)

-3 = k(1)

-3 = k

6 0
3 years ago
How are u supposed to find the area only with the circumference?
seraphim [82]

Answer:

We can find the radius from circumference and then area

Circumference(C) = 2πr

r = C/2π

r = 20/2π

r = 10/π

Area = πr²

Area = π × 10/π × 10/π

Area = 100/π

Area = 100/3.14

Area = 10000/314 = 31.84 cm² (approx)

Area = 32 cm² (Rounding to nearest whole number)

6 0
3 years ago
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800,000,000,000 + 20,000,000,000 + 3,000,000,000 + 50,000,000 + 4,000,000 + 600,000 + 50,000 + 8,000 + 700 + 80 + 6
WITCHER [35]
823054658786 is the answer to your question
3 0
3 years ago
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