Answer:
the surface of area is 14cm to 2cm to 6cm please rate my answer
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Answer:
-2
Step-by-step explanation:
6i-5=-17
6i=-17+5
6i=-12
i=-12/6
i=-2
Answer:
Sum of volumes = (16.6 ± 0.03) cm³
Difference of volumes = (3.8 ± 0.03) cm³
Step-by-step explanation:
Solution
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.
∆V = ± (∆V₁ + ∆V₂)
= ± (0.02 + 0.01) cm³
= ± 0.03 cm³
V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and
V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³
Hence, sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
<u>-TheUnknownScientist</u>