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Rama09 [41]
3 years ago
12

One suggested means of gaining eye contact before reversing is to:____.

Computers and Technology
1 answer:
Orlov [11]3 years ago
5 0

Answer:

<u>hit the vehicle horn</u>

<u>Explanation:</u>

Remember, a driver reversing may easily go unnoticed by pedestrians as the driver may be coming from behind. Thus, a suggested means of gaining the eye contact of pedestrians before reversing is to hit the vehicle horn.

You might be interested in
B. List any four major drawbacks of the first generation computer​
d1i1m1o1n [39]

Answer:

Terribly low storage space, limited to mathematics/computing, required entire rooms to use, and low information yield for hours of processing.

Explanation:

3 0
3 years ago
Programs for embedded devices are often written in assembly language. Some embedded processors have limited instructions, like M
oksano4ka [1.4K]

Answer:

#include <iostream>

using namespace std;

int main()

{

   char address[2];

   int tag, firstBit, secondBit, setNumber;

   int cache[4][2]={{1,5}, {2,4}, {3,2}, {6,0}};

   cout << "Enter the address as hex(in small letters: "<

   cin >> address;

   for (int i < 0; i < 8; i++){

       if (address[0] == '0'){

           tag = 0;

           firstBit = 0;

        } else if (address[0] == '1'){

           tag = 0;

           firstBit = 1;

        } else if (address[0] == '2'){

           tag =1;

           firstBit = 0;

        } else if (address[0] == '3'){

           tag = 1;

           firstBit = 1;

        } else if (address[0] == '4'){

           tag = 2;

           firstBit = 0;

        } else if (address[0] == '5'){

           tag = 2;

           firstBit = 1;

        }  else if (address[0] == '6'){

           tag = 3;

           firstBit = 0;

       } else if (address[0] == '7'){

           tag = 3;

           firstBit = 1;

       }  else if (address[0] == '8'){

           tag = 4;

           firstBit = 0;

       } else if (address[0] == '9'){

           tag = 4;

           firstBit = 1;

       }   else if (address[0] == 'A'){

           tag = 5;

           firstBit = 0;

       } else if (address[0] == 'B'){

           tag = 5;

           firstBit = 1;

       }  else if (address[0] == 'C'){

           tag = 6;

           firstBit = 0;

       } else if (address[0] == 'D'){

           tag = 6;

           firstBit = 1;

        }  else if (address[0] == 'E'){

           tag = 7;

           firstBit = 0;

       } else if (address[0] == 'F'){

           tag = 7;

           firstBit = 1;

       } else{

           cout<<"The Hex number is not valid"<< endl;

        }

   }

   if(address[1]>='0' && address[1]<'8'){

       secondBit = 0;

  }  else if(address[1]=='8'|| address[1]=='9'||(address[1]>='a' && address[1]<='f')){

       secondBit = 1;

   }  else{

       cout<<"The Hex number is not valid"<< endl;  

       return 0;

   }

   setNumber = firstBit * 2 + secondBit;

   if(cache[setNumber][0]==tag || cache[setNumber][1]==tag){

       cout<<"There is a hit";

   } else{

       cout<< "There is a miss";

   }

   return 0;

}

Explanation:

The C++ source code prompts the user for an input for the address variable, then the nested if statement is used to assign the value of the firstBit value given the value in the first index in the address character array. Another if statement is used to assign the value for the secondBit and then the setNumber is calculated.

If the setNumber is equal to the tag bit, Then the hit message is printed but a miss message is printed if not.

4 0
3 years ago
What is a coverage map used for
erastova [34]

Answer/Explanation:

A coverage map shows how much land something takes up or reaches to.

4 0
3 years ago
Read 2 more answers
Create a base class named rectangle that contains lenght and width data members.
kumpel [21]

Answer:

class Rectangle:  

   

   def __init__(self, length, width):

       self.length = length

       self.width = width

       

   

   def area(self):

       area = self.length*self.width

       return area

   

   

class Box (Rectangle):

   

   def __init__(self, length, width, height):

       super().__init__(length, width)

       self.height = height

       

   def volume(self):

       volume = self.length * self.width * self.height

       return volume

   

   def area(self):

       area = 2*(self.length*self.width) + 2*(self.length*self.height) + 2*(self.width*self.height)

       return area

rec_1 = Rectangle(2,4)

box_1 = Box(2,2,6)

print(box_1.length)

print(box_1.area())

   

print(rec_1.length)

print(rec_1.area())

Explanation:

The programming language used is python.

class Rectangle

The class Rectangle is created with attributes length and width.

The class attributes are initialized using the __init__ constructor.

In the rectangle class, a method/function is declared to return the area of the rectangle.

class Box

This class is a child of rectangle and it inherits all its attributes and methods,

It has an additional attribute of depth and its constructor is used to initialize it.

The class contains a volume function, that returns the volume and an override function 'area()' that displaces the area from the parent class.

Finally, some instances of both classes are created.

4 0
3 years ago
A method to accept the number of drawers in the desk as input from the key board. This method returns the number of drawers to t
Julli [10]

Answer:

Following code takes the information about the wood from the user, do the process of calculating the value according to there type and numbers, then add the surcharge to it while giving the answer to the user.

For differentiating the type of woof i used the if then else statement while i used switch case statement for assigning the appropriate value according to the types of the wood will be processing in the program.

The code is given below:

Explanation:

Code:

namespace std;\\ any name instead of std.

{

   class Program

   { \\ starting the main program

       static void Main(string[ ] args)

       {

           int numberOfDrawers = 0;

           string deskWoodType = "o";

           double cost = 0;

           drawersMeth(numberOfDrawers);

           woodTypeMeth(deskWoodType);

           CalculateCostMeth(numberOfDrawers, cost, deskWoodType);

           OutPutCostMeth(deskWoodType , cost, numberOfDrawers);

       }//end main

       private static void drawersMeth(int numberOfDrawers)

       {

           int numOfDrawers;

           Console.WriteLine("Enter the number of desk drawers");

           numOfDrawers = Convert.ToInt16(Console.ReadLine());

           numberOfDrawers = numOfDrawers;

       }//end drawersMeth

       private static string woodTypeMeth(string deskWoodType)

       {

           Console.WriteLine("Enter the desk wood type. (eg. type mahogany, oak, or pine)");

           deskWoodType = Convert.ToString(Console.ReadLine());

           switch (deskWoodType)

           {

               case "mahogany":

                   {

                       deskWoodType = "m";

                       break;

                   }

               case "oak":

                   {

                       deskWoodType = "o";

                       break;

                   }

               case "pine":

                   {

                       deskWoodType = "p";

                       break;

                   }

               default:

                   {

                       deskWoodType = "error";

                       break;

                   }

           }

           return deskWoodType;

       }// end woodTypeMeth

       private static int CalculateCostMeth(string deskWoodType, int numberOfDrawers, int cost)

       {

           int pine = 100;

           int oak = 140;

           int other = 180;

           int surchage = 30;

           if (deskWoodType == "p")

               cost = surchage + (numberOfDrawers *pine );

           else if (deskWoodType == "o")

               cost = surchage + (numberOfDrawers *oak );

           else

               cost = surchage + (numberOfDrawers *other );

           return cost;

       }// end CalculateCostMeth

       private static void OutPutCostMeth(int numberOfDrawers, string deskWoodType, int cost)

       {

           double totalCost = cost;

           Console.WriteLine("The number of drawers is {0}", numberOfDrawers);

           Console.WriteLine("The wood finish you have selected is ", deskWoodType);

           Console.WriteLine("The total cost is {0}", totalCost);

       }//end outputCost

   }//end class

}//end nameSpace

5 0
3 years ago
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