What are the options for this answer?
def dx(fn, x, delta=0.001):
return (fn(x+delta) - fn(x))/delta
def solve(fn, value, x=0.5, maxtries=1000, maxerr=0.00001):
for tries in xrange(maxtries):
err = fn(x) - value
if abs(err) < maxerr:
return x
slope = dx(fn, x)
x -= err/slope
raise ValueError('no solution found')
A person can enrich data in Splunk by
- Preparing to know data that is using Splunk to known the required fields in the data.
- One need to think of this as if one is seeing pieces in a puzzle, then one can notice their shapes.
- The next step is that one need to categorize data as a kind of a preamble before the act of aggregation and reporting.
<h3>What is Enriching Your Data?</h3>
Data enrichment is known to be a kind of an augmentation and it is seen as the act or the process of making better an existing information by the use of a supplementing missing or any kind of incomplete data.
<h3> What is a Lookup?</h3>
Data Lookup is known to be the method used to make plenty any information based on rules.
Hence, A person can enrich data in Splunk by
- Preparing to know data that is using Splunk to known the required fields in the data.
- One need to think of this as if one is seeing pieces in a puzzle, then one can notice their shapes.
- The next step is that one need to categorize data as a kind of a preamble before the act of aggregation and reporting.
Learn more about SPLUNK from
brainly.com/question/26470051
#SPJ1
Answer:
The solution code is written in Python 3
- digits = input("Enter 9 digits: ")
-
- multiplier = 1
- total = 0
-
- for x in digits:
- total += int(x) * multiplier
- multiplier += 1
-
- checksum = total % 11
-
- if(checksum == 10):
- print(digits + "X")
- else:
- print(digits + str(checksum))
Explanation:
Firstly, use input function to get user input for 9 digits (Line 1)
Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)
Then only apply % operator to get the remainder of total and get the checksum (Line 10)
Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)
names = ["Kevin", "Joe", "Thor", "Adam", "Zoe"]
names.sort()
for x in names:
if x == "Thor":
break
else:
print(x)
I made up my own names for the sake of testing my code. I wrote my code in python 3.8. I hope this helps.
